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{ (x^2-13x+40)/sqrt(19x-x^2-78) } <or equal to 0

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Senior Manager
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Joined: 30 Aug 2003
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Kudos [?]: 1 [0], given: 0

{ (x^2-13x+40)/sqrt(19x-x^2-78) } <or equal to 0 [#permalink] New post 13 Mar 2004, 15:40
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{ (x^2-13x+40)/sqrt(19x-x^2-78) } <or equal to 0
Solve for x

(-13,8]
(6,8]
(-6,8]
[5,8]
None of the above

Ps, can someone please refresh my memory on the meaning of ( vs ]
Thanks.
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Pls include reasoning along with all answer posts.
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Senior Manager
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Joined: 02 Mar 2004
Posts: 330
Location: There
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Kudos [?]: 0 [0], given: 0

 [#permalink] New post 14 Mar 2004, 02:53
(x-5)(x-8) sqrt(19x-x^2-78) <= 0 and sqrt(19x-x^2-78) != 0

(1) 5 <= x <=8
(2) x!= 13 or 6
(3) 6 <= x <= 13

Intersection of the above sets= {x | 6 < x <=8} = (6, 8]
  [#permalink] 14 Mar 2004, 02:53
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{ (x^2-13x+40)/sqrt(19x-x^2-78) } <or equal to 0

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