gmatrant wrote:

x^2 > x

=> x^2-x>0

=> x(x-1)>0

so x>0 or x>1.

Just curious x<0 also is valid for the above equation but when I solve mathematically I don't seem to get this as an option

Can you plase let me know where I am going wrong.

Thanks

gmatrant

Hi,

x(x-1)>0 means, x<0 or x>1

for 0<x<1, x(x-1) < 0

Please check the post

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