x^2=>x??? : GMAT Quantitative Section
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 18 Jan 2017, 09:30

# STARTING SOON:

Open Admission Chat with MBA Experts of Personal MBA Coach - Join Chat Room to Participate.

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# x^2=>x???

Author Message
TAGS:

### Hide Tags

Intern
Joined: 13 Jun 2010
Posts: 18
Followers: 0

Kudos [?]: 15 [0], given: 0

### Show Tags

24 May 2013, 14:15
x^2 > x
=> x^2-x>0
=> x(x-1)>0
so x>0 or x>1.

Just curious x<0 also is valid for the above equation but when I solve mathematically I don't seem to get this as an option
Can you plase let me know where I am going wrong.

Thanks
gmatrant
Joined: 28 Mar 2012
Posts: 314
Location: India
GMAT 1: 640 Q50 V26
GMAT 2: 660 Q50 V28
GMAT 3: 730 Q50 V38
Followers: 29

Kudos [?]: 398 [0], given: 23

### Show Tags

24 May 2013, 21:39
gmatrant wrote:
x^2 > x
=> x^2-x>0
=> x(x-1)>0
so x>0 or x>1.

Just curious x<0 also is valid for the above equation but when I solve mathematically I don't seem to get this as an option
Can you plase let me know where I am going wrong.

Thanks
gmatrant

Hi,

x(x-1)>0 means, x<0 or x>1
for 0<x<1, x(x-1) < 0
Please check the post Solving Inequalities

Regards,
Math Expert
Joined: 02 Sep 2009
Posts: 36545
Followers: 7076

Kudos [?]: 93088 [0], given: 10542

### Show Tags

25 May 2013, 02:19
gmatrant wrote:
x^2 > x
=> x^2-x>0
=> x(x-1)>0
so x>0 or x>1.

Just curious x<0 also is valid for the above equation but when I solve mathematically I don't seem to get this as an option
Can you plase let me know where I am going wrong.

Thanks
gmatrant

x^2>x --> x(x-1)>0. Both multiple must have the same sign:

x>0 and x-1>0 (x>1), so x>1.
x<0 and x-1<0 (x<1), so x<0.

Thus x^2>x holds true for x<0 and x>1.

Solving inequalities:
x2-4x-94661.html#p731476
inequalities-trick-91482.html
everything-is-less-than-zero-108884.html?hilit=extreme#p868863

Hope it helps.
_________________
Re: x^2=>x???   [#permalink] 25 May 2013, 02:19
Similar topics Replies Last post
Similar
Topics:
2 X^2<x absolute value question 5 05 Oct 2012, 07:09
4 x^2 - x < 0 4 13 May 2012, 11:54
1 If x2>1? 2 12 Feb 2012, 11:00
1 Square root of X^2? 10 16 Jun 2011, 21:36
2^x+2^x+2^x+2^x = 2^n 5 12 Jan 2011, 21:59
Display posts from previous: Sort by