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Re: |x|=|2y|, what is the value of x-2y? [#permalink]
27 May 2012, 07:35

6

This post received KUDOS

Expert's post

|x|=|2y|, what is the value of x-2y?

First of all |x|=|2y| means that either x=2y or x=-2y.

(1) x+2y = 6. Now, the second case is not possible since if x=-2y then from this statement we would have that -2y+2y=6 --> 0=6, which obviously is not true. So, we have that x=2y, in this case x-2y=2y-2y=0. Sufficient.

(2) xy>0 --> x and y are either both positive or both negative, in any case |x|=|2y| becomes x=2y (if x and y are both negative then |x|=|2y| becomes -x=-2y which is the same as x=2y). Now, if x=2y then x-2y=2y-2y=0. Sufficient.

Re: |x|=|2y|, what is the value of x-2y? [#permalink]
28 May 2012, 08:09

4

This post received KUDOS

Expert's post

kashishh wrote:

Bunuel wrote:

|x|=|2y|, what is the value of x-2y?

First of all |x|=|2y| means that either x=2y or x=-2y.

(1) x+2y = 6. Now, the second case is not possible since if x=-2y then from this statement we would have that -2y+2y=6 --> 0=6, which obviously is not true. So, we have that x=2y, in this case x-2y=2y-2y=0. Sufficient.

(2) xy>0 --> x and y are either both positive or both negative, in any case |x|=|2y| becomes x=2y (if x and y are both negative then |x|=|2y| becomes -x=-2y which is the same as x=2y). Now, if x=2y then x-2y=2y-2y=0. Sufficient.

Answer: D.

Hope it's clear.

Dear Bunuel,

whenever absolute value is analysed, we take two scenarios of <0 and >0. So, why the same is not considered for |x| ?

If x\leq{0} and y\leq{0} then |x|=|2y| expands as -x=-2y --> x=2y; If x\leq{0} and y>{0} then |x|=|2y| expands as -x=2y --> x=-2y; If x>{0} and y\leq{0} then |x|=|2y| expands as x=-2y; If x>{0} and y>{0} then |x|=|2y| expands as x=2y.

So as you can see |x|=|2y| can expand only in two ways x=2y or x=-2y (as shown above ++ and -- are the same, and +- and -+ are the same). _________________

Re: |x|=|2y|, what is the value of x-2y? [#permalink]
28 May 2012, 07:57

Bunuel wrote:

|x|=|2y|, what is the value of x-2y?

First of all |x|=|2y| means that either x=2y or x=-2y.

(1) x+2y = 6. Now, the second case is not possible since if x=-2y then from this statement we would have that -2y+2y=6 --> 0=6, which obviously is not true. So, we have that x=2y, in this case x-2y=2y-2y=0. Sufficient.

(2) xy>0 --> x and y are either both positive or both negative, in any case |x|=|2y| becomes x=2y (if x and y are both negative then |x|=|2y| becomes -x=-2y which is the same as x=2y). Now, if x=2y then x-2y=2y-2y=0. Sufficient.

Answer: D.

Hope it's clear.

Dear Bunuel,

whenever absolute value is analysed, we take two scenarios of <0 and >0. So, why the same is not considered for |x| ?

Re: |x|=|2y|, what is the value of x-2y? [#permalink]
07 Jun 2012, 13:35

Expert's post

BDSunDevil wrote:

Bunuel: can we rewrite |x|=|2y| as x^2-4x^2=0 ? I have solved the problem doing so, but not sure if it algebraically correct. Below what i did:

(x-2y)(x+2y)=0

Using statement 1: (x-2y)*6=0 so, (x-2y)=0. Sufficient

Using statement 2: x=2y [same sign] (x-2y)=0. Sufficient

D

Yes, you can square |x|=|2y| and write x^2=4y^2 --> (x-2y)(x+2y)=0 --> either x=2y or x=-2y the same two options as in my solution above. _________________

Re: |x|=|2y|, what is the value of x-2y? [#permalink]
24 Jul 2012, 15:10

Bunuel wrote:

BDSunDevil wrote:

Bunuel: can we rewrite |x|=|2y| as x^2-4x^2=0 ? I have solved the problem doing so, but not sure if it algebraically correct. Below what i did:

(x-2y)(x+2y)=0

Using statement 1: (x-2y)*6=0 so, (x-2y)=0. Sufficient

Using statement 2: x=2y [same sign] (x-2y)=0. Sufficient

D

Yes, you can square |x|=|2y| and write x^2=4y^2 --> (x-2y)(x+2y)=0 --> either x=2y or x=-2y the same two options as in my solution above.

Hi Bunuel,

I had a query regarding an official statement in the solution to this problem. Actually, the book says that , as, x+2y=6 , so a positive sum indicates that both x and 2y must be positive. However, -4+10= 10+(-4) = 6 =positive sum [both x and 2y are not positive] 10+4=14= positive sum [both x & 2y are positive] isn't it? Please clarify the confusion here..

Re: |x|=|2y|, what is the value of x-2y? [#permalink]
27 May 2013, 14:04

Hello, I am a bit confused regarding absolute value.

If |x|=|2y|, then why why aren't x and 2y both positive? If the abs. value of something (i.e. it's positive value) is equal to something else, doesn't that imply that they are both positive? For example, if x=|2y| doesn't that mean that x is positive?

Also, for #2, xy both have the same signs. If x and y are negative, why would |x|=|2y| become -x = -2y? I get that it's equal to |x|=|2y| but why even take that step? |-x| = |-2y| will always be positive, right?

Bunuel wrote:

|x|=|2y|, what is the value of x-2y?

First of all |x|=|2y| means that either x=2y or x=-2y.

(1) x+2y = 6. Now, the second case is not possible since if x=-2y then from this statement we would have that -2y+2y=6 --> 0=6, which obviously is not true. So, we have that x=2y, in this case x-2y=2y-2y=0. Sufficient.

(2) xy>0 --> x and y are either both positive or both negative, in any case |x|=|2y| becomes x=2y (if x and y are both negative then |x|=|2y| becomes -x=-2y which is the same as x=2y). Now, if x=2y then x-2y=2y-2y=0. Sufficient.

Re: |x|=|2y|, what is the value of x-2y? [#permalink]
27 May 2013, 14:22

Expert's post

WholeLottaLove wrote:

Hello, I am a bit confused regarding absolute value.

If |x|=|2y|, then why why aren't x and 2y both positive? If the abs. value of something (i.e. it's positive value) is equal to something else, doesn't that imply that they are both positive? For example, if x=|2y| doesn't that mean that x is positive?

Also, for #2, xy both have the same signs. If x and y are negative, why would |x|=|2y| become -x = -2y? I get that it's equal to |x|=|2y| but why even take that step? |-x| = |-2y| will always be positive, right?

Bunuel wrote:

|x|=|2y|, what is the value of x-2y?

First of all |x|=|2y| means that either x=2y or x=-2y.

(1) x+2y = 6. Now, the second case is not possible since if x=-2y then from this statement we would have that -2y+2y=6 --> 0=6, which obviously is not true. So, we have that x=2y, in this case x-2y=2y-2y=0. Sufficient.

(2) xy>0 --> x and y are either both positive or both negative, in any case |x|=|2y| becomes x=2y (if x and y are both negative then |x|=|2y| becomes -x=-2y which is the same as x=2y). Now, if x=2y then x-2y=2y-2y=0. Sufficient.

Answer: D.

Hope it's clear.

The absolute value cannot be negative|some \ expression|\geq{0}, or |x|\geq{0} (absolute value of x, |x|, is the distance between point x on a number line and zero, and the distance cannot be negative).

So, if given that x=|2y| then x must be more than or equal to zero (RHS is non-negative thus LHS must also be non-negative).

But in our case we have that |x|=|2y|. In this case x and/or y could be negative. For, example x=-2 and y=-1 --> |x|=2=|2y|.

As for (2): When x\leq{0} then |x|=-x, or more generally when some \ expression\leq{0} then |some \ expression|={-(some \ expression)}. For example: |-5|=5=-(-5);

When x\geq{0} then |x|=x, or more generally when some \ expression\geq{0} then |some \ expression|={some \ expression}. For example: |5|=5.

So, if x<0 and y<0, then |x|=-x and |2y|=-2y --> -x=-2y --> x=2y. If x>0 and y>0, then |x|=x and |2y|=2y --> x=2y, the same as in the first case.

Re: |x|=|2y|, what is the value of x-2y? [#permalink]
27 May 2013, 15:16

Ok, so I get that Abs. value cannot be negative...distance cannot have a negative value.

We are trying to solve for x-2y, so naturally we are trying to determine x-2y. So,

If x=2y then the value of x-2y = 2y-2y = 0 OR If x=-2y (the absolute value of 2y) then the value of x-2y = -2y-2y = -4y, correct?

I guess what throws me off is when you write

When x\leq{0} then |x|=-x. What you're saying is that, for example, |-4| = -(-4) or |-4| = 4. What is the point of writing |-4| = -(-4)

One final thing...In the stem you derived x=2y, x=-2y. Okay, but in #2. one of the cases is xy>0 so we could have -x and -y. If x and y are negative, doesn't that mean that you would substitute -x and y in to get -x=-2(-y) = -x=2y?

I'm sorry for being such a dolt. Sometimes, concepts that I know are very simple are extremely difficult to understand.

Bunuel wrote:

WholeLottaLove wrote:

Hello, I am a bit confused regarding absolute value.

If |x|=|2y|, then why why aren't x and 2y both positive? If the abs. value of something (i.e. it's positive value) is equal to something else, doesn't that imply that they are both positive? For example, if x=|2y| doesn't that mean that x is positive?

Also, for #2, xy both have the same signs. If x and y are negative, why would |x|=|2y| become -x = -2y? I get that it's equal to |x|=|2y| but why even take that step? |-x| = |-2y| will always be positive, right?

Bunuel wrote:

|x|=|2y|, what is the value of x-2y?

First of all |x|=|2y| means that either x=2y or x=-2y.

(1) x+2y = 6. Now, the second case is not possible since if x=-2y then from this statement we would have that -2y+2y=6 --> 0=6, which obviously is not true. So, we have that x=2y, in this case x-2y=2y-2y=0. Sufficient.

(2) xy>0 --> x and y are either both positive or both negative, in any case |x|=|2y| becomes x=2y (if x and y are both negative then |x|=|2y| becomes -x=-2y which is the same as x=2y). Now, if x=2y then x-2y=2y-2y=0. Sufficient.

Answer: D.

Hope it's clear.

The absolute value cannot be negative|some \ expression|\geq{0}, or |x|\geq{0} (absolute value of x, |x|, is the distance between point x on a number line and zero, and the distance cannot be negative).

So, if given that x=|2y| then x must be more than or equal to zero (RHS is non-negative thus LHS must also be non-negative).

But in our case we have that |x|=|2y|. In this case x and/or y could be negative. For, example x=-2 and y=-1 --> |x|=2=|2y|.

As for (2): When x\leq{0} then |x|=-x, or more generally when some \ expression\leq{0} then |some \ expression|\leq{-(some \ expression)}. For example: |-5|=5=-(-5);

When x\geq{0} then |x|=x, or more generally when some \ expression\geq{0} then |some \ expression|\leq{some \ expression}. For example: |5|=5.

So, if x<0 and y<0, then |x|=-x and |2y|=-2y --> -x=-2y --> x=2y. If x>0 and y>0, then |x|=x and |2y|=2y --> x=2y, the same as in the first case.

Re: |x|=|2y|, what is the value of x-2y? [#permalink]
25 Jul 2014, 07:29

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