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x^3*y^4 = 2000. What is y? 1. x is an integer 2. y is an

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x^3*y^4 = 2000. What is y? 1. x is an integer 2. y is an [#permalink] New post 14 May 2008, 01:19
x^3*y^4 = 2000. What is y?

1. x is an integer
2. y is an integer
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Last edited by sondenso on 14 May 2008, 02:09, edited 2 times in total.
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Re: M12- [#permalink] New post 14 May 2008, 01:35
factorise 2000

2*1000
2*2*500
.
.
try cracking down to all primes
.
.
2*2*2*2*5*5*5

(2^4)*(5^3)=2000
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Re: M12- [#permalink] New post 14 May 2008, 01:43
sondenso wrote:
x^3*y^4 = 2000. What is y?

x is an integer
y is an integer


Is it a PS question? Or is it DS ?

Anyways =>
if it is PS,
2000= 2* 10* 10* 10=> 2* 5*2*5*2*5*2 => 5^3 * 2^4 .
Seems to be the only possibility when both x and y are integers.

If it is DS =>
Stt1 : x is an integer => x could be 10 =>
and => x^3 = 1000 => y is not an integer but y=2^(1/4)
but, x = 5 => y = 2
SO, Y cannot be found.
Statement 2 => y is an integer => could be several values again as X is not an integer.

Both togehter STT1 + STT2 => x=5 and y=2 is the only possibility.
So, IMO - C.

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Re: M12- [#permalink] New post 14 May 2008, 02:10
C is my choice and C is not OA!
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Re: M12- [#permalink] New post 14 May 2008, 04:11
I believ this is E..

y can be +-2
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Re: M12- [#permalink] New post 15 May 2008, 04:37
fresinha12 wrote:
I believ this is E..

y can be +-2


Technically speaking you seem to be completely correct.
But somehow... I think we still may be missing someting here.
Can't tell what !!
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Re: M12- [#permalink] New post 15 May 2008, 19:45
fresinha12 wrote:
I believ this is E..

y can be +-2


Thanks fresinha12, you are right, E is OA
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Re: M12-   [#permalink] 15 May 2008, 19:45
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