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(X^3)*(Y^4)=5000. Find Y. (1) X and Y are integers (2) Y>0

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(X^3)*(Y^4)=5000. Find Y. (1) X and Y are integers (2) Y>0 [#permalink] New post 20 Jul 2003, 01:00
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(X^3)*(Y^4)=5000. Find Y.

(1) X and Y are integers
(2) Y>0
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 [#permalink] New post 20 Jul 2003, 06:41
Brainless wrote:
A


Be careful. Y is raised to an even power.
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AkamaiBrah
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Vice President, Midtown NYC Investment Bank, Structured Finance IT
MFE, Haas School of Business, UC Berkeley, Class of 2005
MBA, Anderson School of Management, UCLA, Class of 1993

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 [#permalink] New post 20 Jul 2003, 06:51
Expressing 5000 as product of primes , we get
5000 = 2^3 x 5^4

==> x = 3 and y = 4 . (1) says both x and y are integers.

Am I missing something ?
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 [#permalink] New post 20 Jul 2003, 07:46
2^3 * 5^4 = 5000
2^3 *-5^4 = 5000

are both the same here. You need (2) to find the only solution. Thus, it is C.

Be careful with even powers!
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 [#permalink] New post 20 Jul 2003, 09:25
thanks so much for these problems, they're great!
  [#permalink] 20 Jul 2003, 09:25
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(X^3)*(Y^4)=5000. Find Y. (1) X and Y are integers (2) Y>0

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