X^3 * Y^4 = 5000, is Y=5? (a) Y is a positive integer (b) X : Quant Question Archive [LOCKED]
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# X^3 * Y^4 = 5000, is Y=5? (a) Y is a positive integer (b) X

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CEO
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X^3 * Y^4 = 5000, is Y=5? (a) Y is a positive integer (b) X [#permalink]

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17 Oct 2003, 05:09
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

X^3 * Y^4 = 5000, is Y=5?

(a) Y is a positive integer
(b) X is an integer
Manager
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18 Oct 2003, 12:46
The answer is E

statement 1 :

Let us assume x = 2 , then the answer is YES. But any other value of Y will still satisfy the equation. For example, for Y = 3, there will be some value that will satisfy the original equation. So this st. is not suff.

Statement 2:

NOt suff. Y could be +5 or -5.

Together:

It can be inferred that x > 1. then x = 2 and y = 5 is the only value that will satisfy the equation.

Answer is C
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27 Oct 2003, 12:45
am1974 wrote:
The answer is E

statement 1 :

Let us assume x = 2 , then the answer is YES. But any other value of Y will still satisfy the equation. For example, for Y = 3, there will be some value that will satisfy the original equation. So this st. is not suff.

Statement 2:

NOt suff. Y could be +5 or -5.

Together:

It can be inferred that x > 1. then x = 2 and y = 5 is the only value that will satisfy the equation.

Answer is C

Sorry, is your answer E or C?

What i see is that the only values that will satisfy that equation are X=2 and Y=5 or -5. So all we need to know is weather Y is +ve or -ve. So my answer would be A.

What am i missing?

Thanks
Manager
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27 Oct 2003, 12:55
Hi Camel,

While considering the statement 1, you are assuming that X is integer, but it is not given in statment 1.
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28 Oct 2003, 07:14
am1974 wrote:
Hi Camel,

While considering the statement 1, you are assuming that X is integer, but it is not given in statment 1.

Oay got it, thanks.
28 Oct 2003, 07:14
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# X^3 * Y^4 = 5000, is Y=5? (a) Y is a positive integer (b) X

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