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X+A) (X+B) =X^2+3X+C, what is the value of C? 1. A=1 2. B=2

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X+A) (X+B) =X^2+3X+C, what is the value of C? 1. A=1 2. B=2 [#permalink] New post 15 May 2004, 14:43
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D
E

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(X+A) (X+B) =X^2+3X+C, what is the value of C?

1. A=1
2. B=2
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 [#permalink] New post 15 May 2004, 18:50
D it is

(X+a)(X+b) = X^2+X(a+b)+ab

a+b = 3 ab = c

a) a = 1 then b = 2 and c = 2
b) b = 2 then a = 1 and c = 2
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 [#permalink] New post 15 May 2004, 18:58
D it is. Same technique as Anandnk. Less than 1 min for I did not calculate the individual values.
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 [#permalink] New post 18 May 2004, 11:36
anandnk wrote:
D it is

(X+a)(X+b) = X^2+X(a+b)+ab

a+b = 3 ab = c

a) a = 1 then b = 2 and c = 2
b) b = 2 then a = 1 and c = 2


if u r using a+b=3, shouldn't the answer be C??? You are using both options, aren't you?
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 [#permalink] New post 18 May 2004, 11:42
mirhaque.. in the stem it says 3x.. where as x(a+b)we get
so we can replace 3x as x(a+b),assuming a+b=3
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 [#permalink] New post 18 May 2004, 11:44
Mirahaque,
The given question reduces to A+B =3. Find AB?
All you need to find are the values of the variables A and B.

You can find the value of one variable if you know the value of the other.

Each of the statements gives the value of one variable and this can be used to solve the above eqn.

Hence the answer (D).

Venkat :-)
  [#permalink] 18 May 2004, 11:44
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X+A) (X+B) =X^2+3X+C, what is the value of C? 1. A=1 2. B=2

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