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x and y are 2-digit integers. What is the difference between

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x and y are 2-digit integers. What is the difference between [#permalink] New post 16 Oct 2006, 07:12
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A
B
C
D
E

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x and y are 2-digit integers. What is the difference between two tens digit?

1). x-y=27
2). Units digit of x minus the units digit of y is greater than 3
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 [#permalink] New post 16 Oct 2006, 08:44
x and y are 2-digit integers. What is the difference between two tens digit?

1). x-y=27

2). Units digit of x minus the units digit of y is greater than 3

from one .....insuff ( could be any thing)


from two

insuff

both together tens digits difference = 2 ...my answer is C

FROM TWO UNITS DIGIT OF X> Y

THUS THE 2 FROM 27 IS THE RESULT OF SUBTRACTING THE TENS DIGIT OF Y FROM THAT OF X
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 [#permalink] New post 16 Oct 2006, 10:06
Agree with yezz above my answer is also C
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 [#permalink] New post 16 Oct 2006, 17:52
what about x = 17 and y = -10 ? should we consider such numbers in problems like these..

could any one comment ?
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 [#permalink] New post 16 Oct 2006, 18:50
Code:
from two

insuff


why is 2 insuff?

If you consider the possible sets of number,

It can be -----
SET 1)
18,45
19,46

SET 2)
10,37
20,47

To satisfy condition 2, we have to eliminate set 1
and hence difference between the tens digit is always 2.
Am I missing something OR anything wrong in my analysis :roll: :oops: :x
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 [#permalink] New post 20 Oct 2006, 13:52
I go with (E) , iced_tea - what is the OA ?
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 [#permalink] New post 20 Oct 2006, 16:30
C
assuming they are integers (positive or negative)
-10,17 , -10,-37 and 10,37 are all possibilites. hence tens digit difference will be 2 as -1-1 or -1-(-3) or 1-3

the 2 statements require that the units digits of the 2 no.s be a combination of 0,7 or 1,8 or 2,9 only. these limts ensure that the tens digits are different by only 2 as the 7 in 27 can never round up into the tens digit or the second no.
for eg 33,60 wont do as 3-0 = 3 but 32,59 will as 9-2 = 7 > 3

what am i missing?
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 [#permalink] New post 20 Oct 2006, 19:49
Aren't we forgeting about the negative numbers? If so, then the answer would be E.
Am I way off?
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 [#permalink] New post 20 Oct 2006, 21:34
My answer is also E.

Doesn't even need to be negative numbers.

Could be

38-11 = 27
99-72 = 27

both satisy (1) and (2) but difference of the tens digit in both cases is different

What is OA?
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 [#permalink] New post 21 Oct 2006, 15:57
C

x = 10a + b
y= 10c + d

x - y = 10(a-c) + (b - d)
1) x - y = 27 Insuff
2) b - d > 3 Insuff

Combined we get 27 = 10(a - b) + (b - d)
or 27 - ( b - d) = 10 (a - b)
or a - b = (27 - (b -d))/10
This equation must be satisfied and a - b must be an integer

From above we can safely assume b - d = 7 , hence a - b = 2
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 [#permalink] New post 22 Oct 2006, 15:09
OA icedtea......dont forget us here man :lol:
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 [#permalink] New post 22 Oct 2006, 15:25
yezz wrote:
OA icedtea......dont forget us here man :lol:


sorry for the delay..but I don't have the OA :-(
and my confusion still stands about considering negative numbers !!
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 [#permalink] New post 23 Oct 2006, 08:56
I would say that the question should have specified that the two numbers are positive integers, otherwise the answer would be E. With positive integers we would get C. (Basically the only thing we need to know is if we have borrowed 10 from the tenth digit when we calculate the unit digit).
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  [#permalink] 23 Oct 2006, 08:56
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