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Director
Joined: 22 Aug 2007
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x and y are consecutive positive integers and x>y . Which [#permalink]
 13 Oct 2007, 00:23
x and y are consecutive positive integers and x>y . Which of the following represents all the possible values of y?
A) y>=0
B) y>0
C) y>1
D) y>7
E) y>8
thank you.
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VP
Joined: 08 Jun 2005
Posts: 1171
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Hello Irina,
y = x-1
Lets assume x = 2 then y=1
Choices e,d,c, are wrong
Since y has to be positive then y cannot be equal to zero.
The answer is (B)
But I'm guessing this is what you already got.
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Director
Joined: 03 May 2007
Posts: 903
Schools: University of Chicago, Wharton School
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Re: i think AO is wrong, plz check it [#permalink]
13 Oct 2007, 00:40
IrinaOK wrote: x and y are consecutive positive integers and x>y . Which of the following represents all the possible values of y?
A) y>=0
B) y>0
C) y>1
D) y>7
E) y>8
thank you.
B. Y has to be +ve, so Y is > 0.
we could make it little more interesting:
x and y are consecutive positive integers and x>y. Which of the following represents all the possible values of x?
A) x > -1
B) x > = 0
C) x > 0
D) x > 1
E) x > 2
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Director
Joined: 22 Aug 2007
Posts: 576
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KillerSquirrel wrote: Hello Irina, y = x-1 Lets assume x = 2 then y=1 Choices e,d,c, are wrong Since y has to be positive then y cannot be equal to zero. The answer is (B) But I'm guessing this is what you already got. Hi,
AO is B.
By solving the inequality I also got B, but the changed to C, cuz y>0 includes fractions between zero and 1, meanwhile the stem says y and x are intengers. Wud appreciate your further comments.
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Director
Joined: 03 May 2007
Posts: 903
Schools: University of Chicago, Wharton School
Followers: 4
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IrinaOK wrote: KillerSquirrel wrote: Hello Irina, y = x-1 Lets assume x = 2 then y=1 Choices e,d,c, are wrong Since y has to be positive then y cannot be equal to zero. The answer is (B) But I'm guessing this is what you already got. Hi, AO is B. By solving the inequality I also got B, but the changed to C, cuz y>0 includes fractions between zero and 1, meanwhile the stem says y and x are intengers. Wud appreciate your further comments. x and y are +ve consecutive integers.
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Director
Joined: 22 Aug 2007
Posts: 576
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Re: i think AO is wrong, plz check it [#permalink]
13 Oct 2007, 00:42
Fistail wrote: IrinaOK wrote: x and y are consecutive positive integers and x>y . Which of the following represents all the possible values of y?
A) y>=0
B) y>0
C) y>1
D) y>7
E) y>8
thank you. B. Y has to be +ve, so Y is > 0. we could make it little more interesting: x and y are consecutive positive integers and x>y. Which of the following represents all the possible values of x?A) x > -1 B) x > = 0 C) x > 0 D) x > 1 E) x > 2 like your creative approach. must be C. is it right..
Last edited by IrinaOK on 13 Oct 2007, 00:48, edited 1 time in total.
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Director
Joined: 22 Aug 2007
Posts: 576
Followers: 1
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5
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Fistail wrote: IrinaOK wrote: KillerSquirrel wrote: Hello Irina, y = x-1 Lets assume x = 2 then y=1 Choices e,d,c, are wrong Since y has to be positive then y cannot be equal to zero. The answer is (B) But I'm guessing this is what you already got. Hi, AO is B. By solving the inequality I also got B, but the changed to C, cuz y>0 includes fractions between zero and 1, meanwhile the stem says y and x are intengers. Wud appreciate your further comments. x and y are +ve consecutive integers. I got it, thank you Fistail!
Stem already says that y is not a fraction, little confusing, but i understand.
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Director
Joined: 03 May 2007
Posts: 903
Schools: University of Chicago, Wharton School
Followers: 4
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Re: i think AO is wrong, plz check it [#permalink]
13 Oct 2007, 08:11
IrinaOK wrote: Fistail wrote: IrinaOK wrote: x and y are consecutive positive integers and x>y . Which of the following represents all the possible values of y?
A) y>=0
B) y>0
C) y>1
D) y>7
E) y>8
thank you. B. Y has to be +ve, so Y is > 0. we could make it little more interesting: x and y are consecutive positive integers and x>y. Which of the following represents all the possible values of x?A) x > -1 B) x > = 0 C) x > 0 D) x > 1 E) x > 2 like your creative approach. must be C. is it right.. Should be D since x > y, x cannot be even 1. so x is 2 or > 2.
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Director
Joined: 22 Aug 2007
Posts: 576
Followers: 1
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5
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Re: i think AO is wrong, plz check it [#permalink]
13 Oct 2007, 14:17
Fistail wrote: IrinaOK wrote: Fistail wrote: IrinaOK wrote: x and y are consecutive positive integers and x>y . Which of the following represents all the possible values of y?
A) y>=0
B) y>0
C) y>1
D) y>7
E) y>8
thank you. B. Y has to be +ve, so Y is > 0. we could make it little more interesting: x and y are consecutive positive integers and x>y. Which of the following represents all the possible values of x?A) x > -1 B) x > = 0 C) x > 0 D) x > 1 E) x > 2 like your creative approach. must be C. is it right.. Should be D since x > y, x cannot be even 1. so x is 2 or > 2. Right. It shoud be D.
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CEO
Joined: 29 Mar 2007
Posts: 2618
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Re: i think AO is wrong, plz check it [#permalink]
13 Oct 2007, 23:18
IrinaOK wrote: x and y are consecutive positive integers and x>y . Which of the following represents all the possible values of y?
A) y>=0
B) y>0
C) y>1
D) y>7
E) y>8
thank you.
Argghhh I remember this question. accidentally hit C when I meant B.
Anyway its easy to see the answer.
The main stem says: x and y are POSITIVE CONSECTIVE INTEGERS.
So only B holds. b/c...
A: says that y can be 0. 0 is not a positive value
C: y can be 1.
D and E are just silly.
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Re: i think AO is wrong, plz check it
[#permalink]
13 Oct 2007, 23:18
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