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# x and y are consecutive positive integers and x>y . Which

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Director
Joined: 22 Aug 2007
Posts: 567
Followers: 1

Kudos [?]: 49 [0], given: 0

x and y are consecutive positive integers and x>y . Which [#permalink]

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13 Oct 2007, 00:23
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

x and y are consecutive positive integers and x>y . Which of the following represents all the possible values of y?

A) y>=0
B) y>0
C) y>1
D) y>7
E) y>8

thank you.
VP
Joined: 08 Jun 2005
Posts: 1146
Followers: 7

Kudos [?]: 182 [0], given: 0

[#permalink]

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13 Oct 2007, 00:35
Hello Irina,

y = x-1

Lets assume x = 2 then y=1

Choices e,d,c, are wrong

Since y has to be positive then y cannot be equal to zero.

The answer is (B)

But I'm guessing this is what you already got.

Director
Joined: 03 May 2007
Posts: 886
Schools: University of Chicago, Wharton School
Followers: 6

Kudos [?]: 175 [0], given: 7

Re: i think AO is wrong, plz check it [#permalink]

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13 Oct 2007, 00:40
IrinaOK wrote:
x and y are consecutive positive integers and x>y . Which of the following represents all the possible values of y?

A) y>=0
B) y>0
C) y>1
D) y>7
E) y>8

thank you.

B. Y has to be +ve, so Y is > 0.

we could make it little more interesting:

x and y are consecutive positive integers and x>y. Which of the following represents all the possible values of x?

A) x > -1
B) x > = 0
C) x > 0
D) x > 1
E) x > 2
Director
Joined: 22 Aug 2007
Posts: 567
Followers: 1

Kudos [?]: 49 [0], given: 0

[#permalink]

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13 Oct 2007, 00:40
KillerSquirrel wrote:
Hello Irina,

y = x-1

Lets assume x = 2 then y=1

Choices e,d,c, are wrong

Since y has to be positive then y cannot be equal to zero.

The answer is (B)

But I'm guessing this is what you already got.

Hi,

AO is B.

By solving the inequality I also got B, but the changed to C, cuz y>0 includes fractions between zero and 1, meanwhile the stem says y and x are intengers. Wud appreciate your further comments.
Director
Joined: 03 May 2007
Posts: 886
Schools: University of Chicago, Wharton School
Followers: 6

Kudos [?]: 175 [0], given: 7

[#permalink]

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13 Oct 2007, 00:41
IrinaOK wrote:
KillerSquirrel wrote:
Hello Irina,

y = x-1

Lets assume x = 2 then y=1

Choices e,d,c, are wrong

Since y has to be positive then y cannot be equal to zero.

The answer is (B)

But I'm guessing this is what you already got.

Hi,

AO is B.

By solving the inequality I also got B, but the changed to C, cuz y>0 includes fractions between zero and 1, meanwhile the stem says y and x are intengers. Wud appreciate your further comments.

x and y are +ve consecutive integers.
Director
Joined: 22 Aug 2007
Posts: 567
Followers: 1

Kudos [?]: 49 [0], given: 0

Re: i think AO is wrong, plz check it [#permalink]

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13 Oct 2007, 00:42
Fistail wrote:
IrinaOK wrote:
x and y are consecutive positive integers and x>y . Which of the following represents all the possible values of y?

A) y>=0
B) y>0
C) y>1
D) y>7
E) y>8

thank you.

B. Y has to be +ve, so Y is > 0.

we could make it little more interesting:

x and y are consecutive positive integers and x>y. Which of the following represents all the possible values of x?

A) x > -1
B) x > = 0
C) x > 0
D) x > 1
E) x > 2

like your creative approach. must be C. is it right..

Last edited by IrinaOK on 13 Oct 2007, 00:48, edited 1 time in total.
Director
Joined: 22 Aug 2007
Posts: 567
Followers: 1

Kudos [?]: 49 [0], given: 0

[#permalink]

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13 Oct 2007, 00:43
Fistail wrote:
IrinaOK wrote:
KillerSquirrel wrote:
Hello Irina,

y = x-1

Lets assume x = 2 then y=1

Choices e,d,c, are wrong

Since y has to be positive then y cannot be equal to zero.

The answer is (B)

But I'm guessing this is what you already got.

Hi,

AO is B.

By solving the inequality I also got B, but the changed to C, cuz y>0 includes fractions between zero and 1, meanwhile the stem says y and x are intengers. Wud appreciate your further comments.

x and y are +ve consecutive integers.

I got it, thank you Fistail!

Stem already says that y is not a fraction, little confusing, but i understand.

:
Director
Joined: 03 May 2007
Posts: 886
Schools: University of Chicago, Wharton School
Followers: 6

Kudos [?]: 175 [0], given: 7

Re: i think AO is wrong, plz check it [#permalink]

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13 Oct 2007, 08:11
IrinaOK wrote:
Fistail wrote:
IrinaOK wrote:
x and y are consecutive positive integers and x>y . Which of the following represents all the possible values of y?

A) y>=0
B) y>0
C) y>1
D) y>7
E) y>8

thank you.

B. Y has to be +ve, so Y is > 0.

we could make it little more interesting:

x and y are consecutive positive integers and x>y. Which of the following represents all the possible values of x?

A) x > -1
B) x > = 0
C) x > 0
D) x > 1
E) x > 2

like your creative approach. must be C. is it right..

Should be D since x > y, x cannot be even 1. so x is 2 or > 2.
Director
Joined: 22 Aug 2007
Posts: 567
Followers: 1

Kudos [?]: 49 [0], given: 0

Re: i think AO is wrong, plz check it [#permalink]

### Show Tags

13 Oct 2007, 14:17
Fistail wrote:
IrinaOK wrote:
Fistail wrote:
IrinaOK wrote:
x and y are consecutive positive integers and x>y . Which of the following represents all the possible values of y?

A) y>=0
B) y>0
C) y>1
D) y>7
E) y>8

thank you.

B. Y has to be +ve, so Y is > 0.

we could make it little more interesting:

x and y are consecutive positive integers and x>y. Which of the following represents all the possible values of x?

A) x > -1
B) x > = 0
C) x > 0
D) x > 1
E) x > 2

like your creative approach. must be C. is it right..

Should be D since x > y, x cannot be even 1. so x is 2 or > 2.

Right. It shoud be D.
CEO
Joined: 29 Mar 2007
Posts: 2583
Followers: 19

Kudos [?]: 398 [0], given: 0

Re: i think AO is wrong, plz check it [#permalink]

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13 Oct 2007, 23:18
IrinaOK wrote:
x and y are consecutive positive integers and x>y . Which of the following represents all the possible values of y?

A) y>=0
B) y>0
C) y>1
D) y>7
E) y>8

thank you.

Argghhh I remember this question. accidentally hit C when I meant B.

Anyway its easy to see the answer.

The main stem says: x and y are POSITIVE CONSECTIVE INTEGERS.

So only B holds. b/c...

A: says that y can be 0. 0 is not a positive value
C: y can be 1.
D and E are just silly.
Re: i think AO is wrong, plz check it   [#permalink] 13 Oct 2007, 23:18
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# x and y are consecutive positive integers and x>y . Which

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