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# x and y are consecutive positive integers and x>y x^2

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Senior Manager
Joined: 23 May 2005
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Location: Sing/ HK
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x and y are consecutive positive integers and x>y x^2 [#permalink]  24 Nov 2006, 22:28
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x and y are consecutive positive integers and x>y

x^2 - 1> y^2 -4y +x -1

Which of the ff represents all the possible values of y?

y>=0
y>0
y>1
y>7
y>8
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Impossible is nothing

Senior Manager
Joined: 23 May 2005
Posts: 266
Location: Sing/ HK
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Kudos [?]: 19 [0], given: 0

hi warren,

can you explain how you got y>0? this is my computation

x(x-1)>y(y-4)
(y+1)(y+1-1)>y(y-4)
y+1>y-4

then i'm left with 1>4

??? Is a better way just testing the answer choices?
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Impossible is nothing

VP
Joined: 25 Jun 2006
Posts: 1175
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Hermione wrote:
hi warren,

can you explain how you got y>0? this is my computation

x(x-1)>y(y-4)

(y+1)(y+1-1)>y(y-4)
y+1>y-4

then i'm left with 1>4

??? Is a better way just testing the answer choices?

See the highlighted red part. It is wrong. you can't just eliminate y at both sides, because it is an inequality.

y(y+1) > y( y - 4)
y(y+1) - y(y-4) > 0
y(y+1-y+4) > 0

so y > 0.
Intern
Joined: 13 Oct 2006
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Could you Please suggest me a good site to brush up my Basics on
Equations & Inequations....
Senior Manager
Joined: 23 May 2005
Posts: 266
Location: Sing/ HK
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Kudos [?]: 19 [0], given: 0

Thanks vmuch! I keep forgetting that about inequalities
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Impossible is nothing

Senior Manager
Joined: 23 May 2005
Posts: 266
Location: Sing/ HK
Followers: 1

Kudos [?]: 19 [0], given: 0

navin_aspirant, just check the stickies for inequality rules
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Impossible is nothing

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