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# X and Y are different prime numbers. How many factors does

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X and Y are different prime numbers. How many factors does [#permalink]  21 Feb 2006, 15:50
X and Y are different prime numbers. How many factors does XY^2 have?
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[#permalink]  21 Feb 2006, 18:14
6

1, X, Y, Y^2, XY, XY^2
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SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

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[#permalink]  21 Feb 2006, 18:47
Assume X and Y are 3 and 5.

Then XY^2 = (35)(35)

Factors are = 1,3,5,9,15,25,45,75,225

# of factors = 9
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[#permalink]  21 Feb 2006, 18:55
ywilfred wrote:
Assume X and Y are 3 and 5.

Then XY^2 = (35)(35)

Factors are = 1,3,5,9,15,25,45,75,225

# of factors = 9

I think you read it incorrectly. In your approach if we assume X and Y as 2 and 3 then

XY^2 = (23)(23) or (32)(32) in this case factors can not be determined.

But I think question says X and Y are different prime numbers, (may be one digit or multiple digits). Then we have to find factors of X * Y^2.

Am I right joemama??
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[#permalink]  21 Feb 2006, 19:15
you are right psd, the oa is 6
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[#permalink]  21 Feb 2006, 19:25
joemama142000 wrote:
you are right psd, the oa is 6

I think I read it as (XY)^2
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[#permalink]  21 Feb 2006, 20:54
ywilfred wrote:
Assume X and Y are 3 and 5.

Then XY^2 = (35)(35)

Factors are = 1,3,5,9,15,25,45,75,225

# of factors = 9

Even in this case, arnt factor are numbers which divide the integer which it factorises? , how can 35 be divided by 9 ? . with my exam tomorrow i am getting confused
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[#permalink]  22 Feb 2006, 23:38
If x is 2 and y is 5 then 25^2 is 625. The factors I got was 1, 25, 625, 5, 125. It is not divisible by x. I only got 5 factors?
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[#permalink]  23 Feb 2006, 00:03
jlui4477 wrote:
If x is 2 and y is 5 then 25^2 is 625. The factors I got was 1, 25, 625, 5, 125. It is not divisible by x. I only got 5 factors?

anything muliplied by 2 is even
[#permalink] 23 Feb 2006, 00:03
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# X and Y are different prime numbers. How many factors does

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