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when looking at 1/x + 1/y < 2, i know for a fact that both X and Y can't be 1. because if they are, then 1/1 + 1/1 = 2 which doesn't agree with the question. The only way that the 2 fractions can be smaller is to have either one of the variables bigger than 1 or both variables bigger than 1. Therefore, for sure at least that XY must be greater than 1, therefore my answer is B.

when looking at 1/x + 1/y < 2, i know for a fact that both X and Y can't be 1. because if they are, then 1/1 + 1/1 = 2 which doesn't agree with the question. The only way that the 2 fractions can be smaller is to have either one of the variables bigger than 1 or both variables bigger than 1. Therefore, for sure at least that XY must be greater than 1, therefore my answer is B.

what's the OA?

Couldnt you have one as -1 and the other as or even 0.5?

Both x and y are positive integers, so minimum positive value for one of the variable can be 1 and minimum value for other variable will be greater than 1 in order to satisfy the equation.

Re: 11.35 positive integers [#permalink]
22 Nov 2007, 21:54

bmwhype2 wrote:

X and Y are positive integers. If 1/x + 1/y <2>4 B. XY>1 C. X/Y + Y/X <1> 0 E. none

how can i solve this quickly? not even sure how to start the approach

Getting B.

1/x + 1/y < 2 = (x + y)/xy < 2

Since x and y are +ve integers (given), x & y cannot both be equal to 1. Since one of them has to be greater than 1 (lets say y), then the product of xy has to be greater than 1 as well.