Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

X is prime and y is positive integer, How many different factors of (2^3)*(x^y) are there?

1) x=5 2) y=3

How many different factors of (2^3)*(x^y) are there?
Always just two DIFFERENT: 2 and x
But x could be 2.
So
1) Is suff , just 2 factors
2) Is insuff, because x could be 2 or not, so it could be 1 or 2 different factors.

For any number that is written as the product of primes a^p*b^r*c^q,
where a,b,c are primes, and p,r,q are their powers, the number of factors
=(p+1)(r+1)(q+1). _________________

Well this is how we calculate..
If a number is raised to power of a prime number then the factor is n+1
e.g
2^3 means factors (3+1=4)
Lets see 2^3=8 (1,2,4,8)

Enother eg 2^3 * 5^4
Factors(3+1)*(4+1)=4*5=20
the catch here is tht the numbers should be prime...In our case both 2 and 5 are prime.

One more thing that I would like to add is that the number of distinct product pairs can be given by 1/2 times the number of distinct factors ( except for numbers which are prefect squares).

andy_gr8 wrote:

Well this is how we calculate.. If a number is raised to power of a prime number then the factor is n+1 e.g 2^3 means factors (3+1=4) Lets see 2^3=8 (1,2,4,8)

Enother eg 2^3 * 5^4 Factors(3+1)*(4+1)=4*5=20 the catch here is tht the numbers should be prime...In our case both 2 and 5 are prime.

I´ve done an interview at Accepted.com quite a while ago and if any of you are interested, here is the link . I´m through my preparation of my second...

It’s here. Internship season. The key is on searching and applying for the jobs that you feel confident working on, not doing something out of pressure. Rotman has...