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x/m) (m^2 + n^2 + k^2) = xm+yn+zk? 1. z/k = x/m 2. x/m = y/n

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x/m) (m^2 + n^2 + k^2) = xm+yn+zk? 1. z/k = x/m 2. x/m = y/n [#permalink] New post 11 Sep 2008, 11:55
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(x/m) (m^2 + n^2 + k^2) = xm+yn+zk?

1. z/k = x/m

2. x/m = y/n
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Joined: 07 Nov 2007
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Location: New York
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Kudos [?]: 472 [0], given: 5

Re: DS: Equations [#permalink] New post 11 Sep 2008, 12:30
vksunder wrote:
(x/m) (m^2 + n^2 + k^2) = xm+yn+zk?

1. z/k = x/m

2. x/m = y/n


when
z/k = x/m=y/n

(x/m) (m^2 + n^2 + k^2) = (x/m)*m^2 +(y/n)*n^2++(z/k)*k^2 = xm+yn+zk

C.
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Re: DS: Equations [#permalink] New post 11 Sep 2008, 18:08
vksunder wrote:
(x/m) (m^2 + n^2 + k^2) = xm+yn+zk?

1. z/k = x/m

2. x/m = y/n


solving the equation i question we get
(n^2)( x/m - y/n)+(k^2)(-z/k +x/m) => requires both (1) and (2)
to be equal to 0

IMO C
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Re: DS: Equations   [#permalink] 11 Sep 2008, 18:08
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x/m) (m^2 + n^2 + k^2) = xm+yn+zk? 1. z/k = x/m 2. x/m = y/n

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