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Re: Problem solving [#permalink]
21 Feb 2006, 11:15
This post received KUDOS
x not equal to 0 x=sqrt(4xy-4y^2) then in terms of y, x=
a) 2y b) y c) y/2 d) -4y^2/(1-2y) e) -2y
I would go with A (2Y). Explaination as follows.
Given: x=sqrt(4xy-4y^2) and X <> 0
Squaring both the sides of the equation we get
X^2 = 4XY -4Y^2
So X^2 - 4XY + 4Y^2 = 0
Solving this equation we get
(2Y - X)(2Y - X) = 0
So X = 2Y