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# x not equal to 0 x=sqrt(4xy-4y^2) then in terms of y, x= a)

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Director
Joined: 05 Feb 2006
Posts: 899
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x not equal to 0 x=sqrt(4xy-4y^2) then in terms of y, x= a) [#permalink]  21 Feb 2006, 11:07
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x not equal to 0 x=sqrt(4xy-4y^2) then in terms of y, x=

a) 2y
b) y
c) y/2
d) -4y^2/(1-2y)
e) -2y
Manager
Joined: 16 Sep 2005
Posts: 62
Followers: 1

Kudos [?]: 2 [1] , given: 0

Re: Problem solving [#permalink]  21 Feb 2006, 11:15
1
KUDOS
SimaQ wrote:
x not equal to 0 x=sqrt(4xy-4y^2) then in terms of y, x=

a) 2y
b) y
c) y/2
d) -4y^2/(1-2y)
e) -2y

I would go with A (2Y). Explaination as follows.
Given: x=sqrt(4xy-4y^2) and X <> 0
Squaring both the sides of the equation we get
X^2 = 4XY -4Y^2
So X^2 - 4XY + 4Y^2 = 0
Solving this equation we get
(2Y - X)(2Y - X) = 0
So X = 2Y

Hense the answer is A

I hope this makes sense
_________________

Thanks

Senior Manager
Joined: 11 Jan 2006
Posts: 269
Location: Chennai,India
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Kudos [?]: 3 [0], given: 0

[#permalink]  21 Feb 2006, 21:30
me to A , but i tried back tracking.. substituted the values from the answers in the equation and only A solved

x = 2y , then from the stem x^2 = 4xy-4y^2 , if x=2y then
4y^2 = 4(2y)y - 4y^2= 8y^2-4y^2=4y^2

thus proved
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vazlkaiye porkalam vazltuthan parkanum.... porkalam maralam porkalthan maruma

GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5068
Location: Singapore
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Kudos [?]: 194 [0], given: 0

[#permalink]  21 Feb 2006, 21:33
x^2 = 4xy - 4y^2
x^2 - 4xy + 4y^2 = 0
(x-2y)^2 = 0
x = 2y
[#permalink] 21 Feb 2006, 21:33
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# x not equal to 0 x=sqrt(4xy-4y^2) then in terms of y, x= a)

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