x>y? (1) xy>1 (2) x/y > 1

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x>y? (1) xy>1 (2) x/y > 1 [#permalink]

28 Nov 2005, 06:42

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23. x>y?

(1) xy>1
(2) x/y > 1
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Auge um Auge, Zahn um Zahn :twisted: !

Last edited by gamjatang on 01 Dec 2005, 00:18, edited 1 time in total.

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28 Nov 2005, 07:24

Let me give it a try..... :-D

A) xy>1 => x > 1/y Not Sufficient.

B) x/y>1 => x>y Sufficient.

C

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28 Nov 2005, 07:31

positive soul wrote:

Let me give it a try..... :-D

A) xy>1 => x > 1/y Not Sufficient.

B) x/y>1 => x>y Sufficient.

C

you forgot the case in which y is negative ..coz if it's negative, multiplying two sides of the inequality in B causes the change in direction of the inequality :wink:

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28 Nov 2005, 07:33

btw, i like Tom Hanks :wink:

...he played lively the role in Forest Gump

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Re: DS - (AG) X>Y? [#permalink]

28 Nov 2005, 07:41

gamjatang wrote:

23. x>y?

(1) xy>1
(2) x/y > 1

1) xy > 1
Take two cases x = 2, y = 1 -- x > y
x = -2, y = -1 -- X < y Insuff

2) x/y > 1
Take two cases x = 2, y = 1 -- x > y
x = -2, y = -1 -- X < y Insuff

Both together, insufficient
Ans = E

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28 Nov 2005, 08:14

E)...question asks x-y>0 ?

1) xy>1. not enough. x can be 4 or -4 and y can be 3 or -3. insuff

2) x/y>1 => (x-y)/y>0...x-y>0 and y>0 OR x-y<0 and y<0. insuff

1)+2) both sets (4,3) and (-4,-3) satisfy both statments...insuff
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28 Nov 2005, 11:21

Yep...you are right....... :shock:

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28 Nov 2005, 12:15

E

23. x>y?

(1) xy>1
let x = -4 , y = -3 xy =12 > 1
let x = 4 , y = 3 xy =12 >
NS

(2) x/y > 1
let x = -6 , y = -3 x/y =2 > 1
let x = 6 , y = 3 x/y = 2 > 1

NS

taking together
let x = -6 , y = -3 x/y =2 > 1 & xy > 1
let x = 6 , y = 3 x/y = 2 > 1 & xy > 1

NS

E

[#permalink] 28 Nov 2005, 12:15

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x>y? (1) xy>1 (2) x/y > 1

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