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# x>y? (1) xy>1 (2) x/y > 1

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Director
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x>y? (1) xy>1 (2) x/y > 1 [#permalink]  28 Nov 2005, 05:42
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23. x>y?

(1) xy>1
(2) x/y > 1
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Auge um Auge, Zahn um Zahn !

Last edited by gamjatang on 30 Nov 2005, 23:18, edited 1 time in total.
Manager
Joined: 24 Oct 2005
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Let me give it a try.....

A) xy>1 => x > 1/y Not Sufficient.

B) x/y>1 => x>y Sufficient.

C
SVP
Joined: 24 Sep 2005
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positive soul wrote:
Let me give it a try.....

A) xy>1 => x > 1/y Not Sufficient.

B) x/y>1 => x>y Sufficient.

C

you forgot the case in which y is negative ..coz if it's negative, multiplying two sides of the inequality in B causes the change in direction of the inequality
SVP
Joined: 24 Sep 2005
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btw, i like Tom Hanks ...he played lively the role in Forest Gump
Director
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Re: DS - (AG) X>Y? [#permalink]  28 Nov 2005, 06:41
gamjatang wrote:
23. x>y?

(1) xy>1
(2) x/y > 1

1) xy > 1
Take two cases x = 2, y = 1 -- x > y
x = -2, y = -1 -- X < y Insuff

2) x/y > 1
Take two cases x = 2, y = 1 -- x > y
x = -2, y = -1 -- X < y Insuff

Both together, insufficient
Ans = E
VP
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1) xy>1. not enough. x can be 4 or -4 and y can be 3 or -3. insuff

2) x/y>1 => (x-y)/y>0...x-y>0 and y>0 OR x-y<0 and y<0. insuff

1)+2) both sets (4,3) and (-4,-3) satisfy both statments...insuff
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If your mind can conceive it and your heart can believe it, have faith that you can achieve it.

Manager
Joined: 24 Oct 2005
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Kudos [?]: 127 [0], given: 0

Yep...you are right.......
Director
Joined: 27 Jun 2005
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E

23. x>y?

(1) xy>1
let x = -4 , y = -3 xy =12 > 1
let x = 4 , y = 3 xy =12 >
NS

(2) x/y > 1
let x = -6 , y = -3 x/y =2 > 1
let x = 6 , y = 3 x/y = 2 > 1

NS

taking together
let x = -6 , y = -3 x/y =2 > 1 & xy > 1
let x = 6 , y = 3 x/y = 2 > 1 & xy > 1

NS

E
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