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# X/Y = 5.35 If x and y are positive integers, then what is

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X/Y = 5.35 If x and y are positive integers, then what is [#permalink]  21 Jun 2011, 00:16
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Question Stats:

44% (02:10) correct 55% (01:12) wrong based on 47 sessions
X/Y = 5.35

If x and y are positive integers, then what is the value of x?

(1) When y is divided by x, the remainder is 20.

(2) When x is divided by y, the remainder is 7.

Master Gmat 22
[Reveal] Spoiler: OA

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Kudos [?]: 255 [0], given: 35

Re: confusing arithmetic equation [#permalink]  21 Jun 2011, 00:34
x = 5y + 0.35y

So remainder is 0.35y - (A)

Again,

y/x = 1/5.35 = 100/535 = 20/107 - (B)

(1)
Clearly, from (B), x = 107 as remainder is always less than divisor
Sufficient

(2)

Clearly, from (A), 0.35y = 7

So 0.05Y = 1 => y = 20

Hence X can be found as x = 5.35 * 20 = 107

Sufficient

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Re: confusing arithmetic equation [#permalink]  05 Sep 2011, 09:32
1
KUDOS
Quote:
X/Y = 5.35

If x and y are positive integers, then what is the value of x?

(1) When y is divided by x, the remainder is 20.

(2) When x is divided by y, the remainder is 7.

Master Gmat 22

X/Y=5 + 7/20
--> Y is a multiple of 20
--> remainder is a multiple of 7

As such:
Y=20 (or multiple of 20)
remainder=7 (or multiple of 7)
--> lowest possible value of X: 5(20)+7 = 107

From Statement 1
Y/X= Integer, remainder 20
20/107 = 0 + 20
Sufficient

From Statement 2
X = multiple of Y + 7
107=5(20)+7
Sufficient

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Re: confusing arithmetic equation   [#permalink] 05 Sep 2011, 09:32
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