Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
It appears that you are browsing the GMAT Club forum unregistered!
Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club
Registration gives you:
Tests
Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.
Applicant Stats
View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more
Books/Downloads
Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
x/y=5.35 If x and y are positive integers, then what is the value of x?
(1) When y is divided by x, the remainder is 20.
(2) When x is divided by y, the remainder is 7.
I surprised myself at the pace which I solved this one. Looks like a easy one.
Given x/y = 5.35 = 5 + 0.35
5 + 0.35 can be represented as 5 + 35/100 => 5 + 7/20 => 107/20
Hence x/y is 107/20.
Let us look at the statements:
1) Given y/x = some integer + 20 (remainder). We know that x/y = 107/20. Hence y/x = 20/107 -- gives us 20 as the remainder and 0 as the quotient. Sufficient.
2) Given x/y = 7. Yes this is also possible 107/20 gives us a remainder of 7. Sufficient.
Answer D. _________________
Support GMAT Club by putting a GMAT Club badge on your blog
x/y=5.35 If x and y are positive integers, then what is the value of x?
(1) When y is divided by x, the remainder is 20.
(2) When x is divided by y, the remainder is 7.
x/y = 5.35 = 535/100 = 107/20
x and y will be of the form 107z and 20z
(1) y is less than x so when divided by x the remainder will be y itself. So y=20. If y=20, x=107. Sufficient
(2) x divided by y leaves remainder 7. note that 107z = 5*(20z) + 7z and that 7z < 20z so then the remainder is always 7z. but we know remainder is 7. so z=1 hence x=107 & y=20 Sufficient
From Statement 2 X = multiple of Y + 7 107=5(20)+7 Sufficient
Answer: D _________________
"The best day of your life is the one on which you decide your life is your own. No apologies or excuses. No one to lean on, rely on, or blame. The gift is yours - it is an amazing journey - and you alone are responsible for the quality of it. This is the day your life really begins." - Bob Moawab
Your reasoning worked to reach D in this case, but we have to be careful with setups like this. From the statements alone, we just know that x/y = 107/20. x & y could be any multiple of those numbers, and we don't necessarily want to try to confirm that they fit those particular values.
To solve this, we need to know that the fractional part is equal to the remainder over the divisor. Since statement 2 uses the same setup as our original equation, let’s start there:
2) .35=7/y .35y=7 (7/20)y=7 y=7(20/7) y=20
Once we know that y=20, we can plug into our original equation:
x/y=5.35 x/20=5.35 x=107 Sufficient
1) We can’t use the same approach for statement 1, because we don’t know the fractional part when y is divided by x. However, we might notice that since x/y >1, y/x must be less than 1. In other words, if y goes into x more than 5 times, we know that x is bigger than y, so y can’t go into x at all!
If x goes into y zero times, then y/x = 0 r 20. Therefore, the remainder *is* our value for y. y=20
From there, we can proceed as before to find x=107. Sufficient.
I hope this helps! _________________
Dmitry Farber | Manhattan GMAT Instructor | New York
Re: x/y =5.35 If x and y are positive integers, then what is the [#permalink]
11 Aug 2013, 22:28
Gem of a question :
hard to get the statement 1 inference , although statement 2 is easy to infer.
From above post what I can understand is that:
Since X/Y >1 => Y has to be less than X
Therefore,
When Y is divided by X then the quotient will have to be '0', since if remainder is other than '0' than Y will have a greater value than X which will contradict that X>Y as per question stem so when Y is divided by X the quotient's value should be '0' only . Hence Y=20 so we can get the value of X using question stem
Rgds, TGC ! _________________
Rgds, TGC! _____________________________________________________________________ I Assisted You => KUDOS Please _____________________________________________________________________________
Re: X/Y = 5.35 If x and y are positive integers, then what is [#permalink]
26 Jun 2014, 20:30
Hello from the GMAT Club BumpBot!
Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________
Re: x/y=5.35 If x and y are positive integers, then what is the [#permalink]
20 Aug 2015, 10:28
Hello from the GMAT Club BumpBot!
Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________
That is not correct reto. Although you did end up getting the correct answer, make sure to apply the concepts correctly. This is a very good example of how to interpret the divisbility formula.
When you write the divisbility formula, you get,
x=yp+r , where p is a positive integer.
Thus you get, x/y=p+r/y and this r/y=0.35 (x/y \(\neq\).35. This is where you are making a mistake)
Per statement 2, r=7 and thus y=20, giving you x=107.
Per statement 1, y/x=q+20 , you also know that x/y=5.35 ---> x>y thus when you divide y/x (think 30/67 for example, you will geta quotient of 0 and remainder as 30, the dividend itself!!), you get 0 as the quotient and 20 as the remainder.
Thus, y must be = 20 , again giving you x = 107.
Thus both statements are sufficient individually, giving you D as the correct answer.
As I’m halfway through my second year now, graduation is now rapidly approaching. I’ve neglected this blog in the last year, mainly because I felt I didn’...
Perhaps known best for its men’s basketball team – winners of five national championships, including last year’s – Duke University is also home to an elite full-time MBA...
Hilary Term has only started and we can feel the heat already. The two weeks have been packed with activities and submissions, giving a peek into what will follow...