x/y=5.35 If x and y are positive integers, then what is the

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x/y=5.35 If x and y are positive integers, then what is the [#permalink]

05 Oct 2010, 19:39

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x/y=5.35
If x and y are positive integers, then what is the value of x?

(1) When y is divided by x, the remainder is 20.

(2) When x is divided by y, the remainder is 7.

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Re: DS [#permalink]

05 Oct 2010, 19:49

TomB wrote:

x/y=5.35
If x and y are positive integers, then what is the value of x?

(1) When y is divided by x, the remainder is 20.

(2) When x is divided by y, the remainder is 7.

I surprised myself at the pace which I solved this one. Looks like a easy one.

Given x/y = 5.35 = 5 + 0.35

5 + 0.35 can be represented as 5 + 35/100 => 5 + 7/20 => 107/20

Hence x/y is 107/20.

Let us look at the statements:

1) Given y/x = some integer + 20 (remainder). We know that x/y = 107/20. Hence y/x = 20/107 -- gives us 20 as the remainder and 0 as the quotient. Sufficient.

2) Given x/y = 7. Yes this is also possible 107/20 gives us a remainder of 7. Sufficient.

Answer D.
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Re: DS [#permalink]

06 Oct 2010, 00:12

TomB wrote:

x/y=5.35
If x and y are positive integers, then what is the value of x?

(1) When y is divided by x, the remainder is 20.

(2) When x is divided by y, the remainder is 7.

x/y = 5.35 = 535/100 = 107/20

x and y will be of the form 107z and 20z

(1) y is less than x so when divided by x the remainder will be y itself. So y=20. If y=20, x=107. Sufficient

(2) x divided by y leaves remainder 7.
note that 107z = 5*(20z) + 7z
and that 7z < 20z
so then the remainder is always 7z. but we know remainder is 7. so z=1
hence x=107 & y=20
Sufficient

Answer is (d)
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Re: DS [#permalink] 06 Oct 2010, 00:12

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x/y=5.35 If x and y are positive integers, then what is the

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x/y=5.35 If x and y are positive integers, then what is the

x/y=5.35 If x and y are positive integers, then what is the

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