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Re: x, y, and z are consecutive integers, and x < y < z. [#permalink]

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26 Jan 2010, 00:34

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This post received KUDOS

joyseychow wrote:

x, y, and z are consecutive integers, and x < y < z. What is the average of x, y, and z?

(1) x = 11

(2) The average of y and z is 12.5.

[spoiler]Can we considered prime numbers as an option of consecutive integers? Also, how can stmt2 be sufficient?

OA is D[/spoiler]

D.

Stat 1: X=11 this is enough to determine Y=12 and Z=13. You can compute the average after knowing all the values. Suff.

Stat 2: Y and Z has an average of 12.5 and they have to be consecutive numbers. There are no other choices other than Y being 12 and Z being 13, since Y<Z. Any other combination of Y,Z yielding average of 12.5 would not be consecutive integers. (e.g. Y=11, Z=14). With that in mind, X must be 11 and hence sufficient.

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