x+y)/Z>0 is x<0? (1) x<y (2) z<0

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x+y)/Z>0 is x<0? (1) x<y (2) z<0 [#permalink]

14 Jun 2011, 07:43

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(x+y)/Z>0 is x<0?
(1) x<y
(2) z<0

[Reveal] Spoiler: OA

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Re: Is x<0 [#permalink]

14 Jun 2011, 07:50

Baten80 wrote:

(x+y)/Z>0 is x<0?
(1) x<y
(2) z<0

Clean C
st. 1 doesnt tell abt Z . insufficient
st2. nothing abt X and Y . insufficient

X<Y and Z<0

(X+y)/Z >0 and Z<0 means X+y <0
we know X<Y
hence X<0

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Re: Is x<0 [#permalink]

14 Jun 2011, 09:18

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Baten80 wrote:

(x+y)/Z>0 is x<0?
(1) x<y
(2) z<0

Sol:

\frac{x+y}{z} > 0
Means,

If z>0, x+y>0
If z<0, x+y<0

1. x<y
x=1, y=2, z=3;
\frac{x+y}{z}=\frac{1+2}{3}=1 AND x>0

x=-2, y=-1, z=-3;
\frac{x+y}{z}=\frac{-1-2}{-3}=1 BUT x<0

Not Sufficient.

2. z<0

Means;
x+y<0
x=-10; y=1; x+y= -9; x<0
x=1; y=-10; x+y=-9; x>0

Not Sufficient.

Combining both;
From stem we know,
If z<0, x+y<0-----1

From St1, x<y OR x-y<0-------2

Adding 1 and 2;
2x<0
OR
x<0
Sufficient.

Ans: "C"
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Re: Is x<0 [#permalink] 14 Jun 2011, 09:18

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x+y)/Z>0 is x<0? (1) x<y (2) z<0

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x+y)/Z>0 is x<0? (1) x<y (2) z<0

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