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x+y)/Z>0 is x<0? (1) x<y (2) z<0

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Status: No dream is too large, no dreamer is too small
Joined: 14 Jul 2010
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Kudos [?]: 402 [0], given: 39

x+y)/Z>0 is x<0? (1) x<y (2) z<0 [#permalink] New post 14 Jun 2011, 06:43
00:00
A
B
C
D
E

Difficulty:

  45% (medium)

Question Stats:

77% (01:26) correct 23% (00:32) wrong based on 13 sessions
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Joined: 26 May 2005
Posts: 565
Followers: 18

Kudos [?]: 146 [0], given: 13

Re: Is x<0 [#permalink] New post 14 Jun 2011, 06:50
Baten80 wrote:
(x+y)/Z>0 is x<0?
(1) x<y
(2) z<0


Clean C
st. 1 doesnt tell abt Z . insufficient
st2. nothing abt X and Y . insufficient

X<Y and Z<0

(X+y)/Z >0 and Z<0 means X+y <0
we know X<Y
hence X<0
1 KUDOS received
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Kudos [?]: 1181 [1] , given: 376

Re: Is x<0 [#permalink] New post 14 Jun 2011, 08:18
1
This post received
KUDOS
Baten80 wrote:
(x+y)/Z>0 is x<0?
(1) x<y
(2) z<0


Sol:

\(\frac{x+y}{z} > 0\)
Means,

If \(z>0\), \(x+y>0\)
If \(z<0\), \(x+y<0\)

1. x<y
x=1, y=2, z=3;
\(\frac{x+y}{z}=\frac{1+2}{3}=1\) AND x>0

x=-2, y=-1, z=-3;
\(\frac{x+y}{z}=\frac{-1-2}{-3}=1\) BUT x<0

Not Sufficient.

2. z<0

Means;
\(x+y<0\)
x=-10; y=1; x+y= -9; x<0
x=1; y=-10; x+y=-9; x>0

Not Sufficient.

Combining both;
From stem we know,
If \(z<0\), \(x+y<0\)-----1

From St1, \(x<y\) OR \(x-y<0\)-------2

Adding 1 and 2;
\(2x<0\)
OR
\(x<0\)
Sufficient.

Ans: "C"
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Re: Is x<0   [#permalink] 14 Jun 2011, 08:18
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