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Manager
Joined: 06 Apr 2010
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x+y+z is even, is x*y*z even? 1) x*y even 2) y*z odd How [#permalink]
 16 Jun 2010, 22:50
Question Stats:
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x+y+z is even, is x*y*z even?
1) x*y even
2) y*z odd
How does one answer if the variables are not specified as integers? Does gmat try to sneak in this kind of question? thanks!
P/S : I don't know the OA
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Manager
Joined: 30 May 2010
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In order for a number to be even or odd, it must be an integer.
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I hate such questions!!  If x+y+z is even, & xyz are integers then in any case xyz will also be even. But the question has given us two options, hence assuming that x,y & z are not integers or not all integers. e.g x=3.5 y=4.5 z=2 or vice versa. I think its "C"
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Manager
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Here's my solution any even or odd number is an integer. Given condition -> x+y+z = even, so only two possibles either 2 of them are odd and one is even, or all three are even Stmt 1 - considering both the possibilities, if x*y is even means withe x can be odd or y can be even or vice versa, or both can be even. Now if z is odd or even, the result will be an even integer. SUFFICIENT Stmt 2 - y*z is odd, means both should be odd. That means x is even (to satisfy given condition). the result will be an even integer. SUFFICIENT I will go with D Whts the OA?
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Manager
Joined: 07 Jun 2010
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Location: United States
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x+y+z is even, is x*y*z even?
1) x*y even
2) y*z odd
x+y+z = even , here we have 4 scenarios
1. E + E + E
2. O + O + E
3. O + e + O
4. E + O + O
(I) X * Y = EVEN
SO WE HAVE FOLLOWING POSSIBILITIES
X Y
EVEN EVEN
EVEN ODD
ODD EVEN
SO CLEARLY 1 IS INSUFFI
(2) Y*Z = ODD
Y Z
ODD ODD
SO CLEARLY 2 IS INSUFFI
SO COMBINING BOTH MEANS EVEN ODD ODD WE CAN SOLVE
ANS C
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Intern
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you r wrong. for a yes/no que the answer is d.
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GMAT Club team member
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Eden wrote: x+y+z is even, is x*y*z even?
1) x*y even
2) y*z odd
How does one answer if the variables are not specified as integers? Does gmat try to sneak in this kind of question? thanks!
P/S : I don't know the OA Note that we are not told that x, y, and z are integrs. Given: x+y+z=even. Question: xyz=even? (1) xy=even --> if x=\frac{4}{5}, y=5 and z=\frac{1}{5}( xy=even=4, x+y+z=6=even), then the answer would be NO as xyz=\frac{4}{5}\neq{integer} but if x=0 and y+z=any \ odd+any \ odd=some \ even, then the answer would be YES. Not sufficient. (2) yz=odd --> again if x=\frac{4}{5}, y=5 and z=\frac{1}{5}( yz=odd=1, x+y+z=6=even), then the answer would be NO as xyz=\frac{4}{5}\neq{integer} but if x=0 and y+z=any \ odd+any \ odd=some \ even, then the answer would be YES. Not sufficient. (1)+(2) the same here: if x=\frac{4}{5}, y=5 and z=\frac{1}{5}, then the answer would be NO as xyz=\frac{4}{5}\neq{integer} but if x=0 and y+z=any \ odd+any \ odd=some \ even, then the answer would be YES. Not sufficient. Answer: E.
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Intern
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u r right. nice one. tnx
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