Here's my solution
any even or odd number is an integer.
Given condition -> x+y+z = even, so only two possibles either 2 of them are odd and one is even, or all three are even
Stmt 1 - considering both the possibilities, if x*y is even means withe x can be odd or y can be even or vice versa, or both can be even. Now if z is odd or even, the result will be an even integer. SUFFICIENT
Stmt 2 - y*z is odd, means both should be odd. That means x is even (to satisfy given condition). the result will be an even integer. SUFFICIENT
I will go with D
Whts the OA?
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