Find all School-related info fast with the new School-Specific MBA Forum

It is currently 29 Aug 2014, 12:15

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

Xander, Yolanda, and Zelda each have at least one hat. Zelda

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
1 KUDOS received
Intern
Intern
avatar
Joined: 23 Aug 2011
Posts: 47
Followers: 0

Kudos [?]: 6 [1] , given: 4

Xander, Yolanda, and Zelda each have at least one hat. Zelda [#permalink] New post 07 Oct 2011, 21:23
1
This post received
KUDOS
00:00
A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

46% (02:33) correct 54% (01:27) wrong based on 84 sessions
Xander, Yolanda, and Zelda each have at least one hat. Zelda has more hats than Yolanda, who has more than Xander. Together, the total number of hats the three people have is 12. How many hats does Yolanda have?

(1) Zelda has no more than 5 hats more than Xander.
(2) The product of the numbers of hats that Xander, Yolanda, and Zelda have is less than 36.
[Reveal] Spoiler: OA
1 KUDOS received
Math Forum Moderator
avatar
Joined: 20 Dec 2010
Posts: 2047
Followers: 128

Kudos [?]: 904 [1] , given: 376

GMAT Tests User
Re: DS [#permalink] New post 07 Oct 2011, 23:35
1
This post received
KUDOS
kkalyan wrote:
Xander, Yolanda, and Zelda each have at least one hat. Zelda has more hats than Yolanda, who has more than Xander. Together, the total number of hats the three people have is 12. How many hats does Yolanda have?

1. Zelda has no more than 5 hats more than Xander.
2. The product of the numbers of hats that Xander, Yolanda, and Zelda have is less than 36.


kkalyan: Please tag the source correctly. It is a Manhattan GMAT question, not a GMAT Prep question. Also, please try to give a unique name for the subject.

MGMAT DS: Hats owned by Xander, Yolanda, and Zelda

Z>Y>X
Z+Y+X=12

1) Z-X<=5
1, 5, 6
2, 4, 6
Not Sufficient.

2) X.Y.Z<36
1, 5, 6
1, 2, 9
Not Sufficient.

Combined;
{1, 5, 6}
Y=5

Ans: "C"
_________________

~fluke

Get the best GMAT Prep Resources with GMAT Club Premium Membership

Expert Post
1 KUDOS received
Math Expert
User avatar
Joined: 02 Sep 2009
Posts: 25204
Followers: 3418

Kudos [?]: 25029 [1] , given: 2699

Re: DS [#permalink] New post 22 Apr 2012, 20:44
1
This post received
KUDOS
Expert's post
anushapolavarapu wrote:
Hi fluke,

what about the combination {1,4,7}. even this satisfies the 2 conditions right.
1+4+7=12(x<y<z) and
1*4*7=28 which is < 36


So, I think answer should be E. Can you please help.


Welcome to GMAT Club. Below is an answer to your doubt.

The case when x=1, y=4, and z=7 does not satisfy the first statement, which says that z-x\leq{5} (Zelda has no more than 5 hats more than Xander). Also notice that there are some cases missing for (1) and (2) in fluke's solution.

Complete solution:

Xander, Yolanda, and Zelda each have at least one hat. Zelda has more hats than Yolanda, who has more than Xander. Together, the total number of hats the three people have is 12. How many hats does Yolanda have?

Given: x<y<z and x+y+z=12. Question: y=?

Now, only following 7 cases are possible;

X-Y-Z
1-2-9
1-3-8
1-4-7
1-5-6
2-3-7
2-4-6
3-4-5

(1) Zelda has no more than 5 hats more than Xander --> z-x\leq{5} --> first 3 cases are out and only following cases are left: {1, 5, 6}, {2, 3, 7}, {2, 4, 6}, and {3, 4, 5}. Not sufficient.

(2) The product of the numbers of hats that Xander, Yolanda, and Zelda have is less than 36 --> last 3 cases are out and only following cases are left: {1, 2, 9}, {1, 3, 8}, {1, 4, 7}, and {1, 5, 6}. Not sufficient.

(1)+(2) There is only one case common for (1) and (2): {1, 5, 6}, so z=6. Sufficient.

Answer: C.

Hope it's clear.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
25 extra-hard Quant Tests

Get the best GMAT Prep Resources with GMAT Club Premium Membership

Intern
Intern
avatar
Joined: 14 Oct 2011
Posts: 1
Followers: 0

Kudos [?]: 0 [0], given: 19

Re: DS [#permalink] New post 22 Apr 2012, 18:27
Hi fluke,

what about the combination {1,4,7}. even this satisfies the 2 conditions right.
1+4+7=12(x<y<z) and
1*4*7=28 which is < 36


So, I think answer should be E. Can you please help.
Senior Manager
Senior Manager
User avatar
Joined: 01 Apr 2010
Posts: 300
Location: Kuwait
Schools: Sloan '16 (M)
GMAT 1: 710 Q49 V37
GPA: 3.2
WE: Information Technology (Consulting)
Followers: 4

Kudos [?]: 54 [0], given: 11

GMAT Tests User
Re: DS [#permalink] New post 23 Apr 2012, 09:17
anushapolavarapu wrote:
Hi fluke,

what about the combination {1,4,7}. even this satisfies the 2 conditions right.
1+4+7=12(x<y<z) and
1*4*7=28 which is < 36


So, I think answer should be E. Can you please help.


{1,4,7}. Z has more than 5 hats than X does. Again great explanation above.

Do you suggest during these type of questions to spend time writing out all combination possibilities at the start?
Expert Post
Math Expert
User avatar
Joined: 02 Sep 2009
Posts: 25204
Followers: 3418

Kudos [?]: 25029 [0], given: 2699

Xander, Yolanda, and Zelda each have at least one hat. Zelda [#permalink] New post 23 Apr 2012, 09:37
Expert's post
aalba005 wrote:
anushapolavarapu wrote:
Hi fluke,

what about the combination {1,4,7}. even this satisfies the 2 conditions right.
1+4+7=12(x<y<z) and
1*4*7=28 which is < 36


So, I think answer should be E. Can you please help.


{1,4,7}. Z has more than 5 hats than X does. Again great explanation above.

Do you suggest during these type of questions to spend time writing out all combination possibilities at the start?


It depends how many possible combinations are there. Luckily there are only 7 for this question, so it's not hard to write them all down. In this case everything will be in front of you so you won't miss any case while solving.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
25 extra-hard Quant Tests

Get the best GMAT Prep Resources with GMAT Club Premium Membership

Director
Director
avatar
Joined: 17 Apr 2013
Posts: 514
Concentration: Entrepreneurship, Leadership
Schools: HBS '16
GMAT Date: 11-30-2013
GPA: 3.3
Followers: 3

Kudos [?]: 26 [0], given: 239

CAT Tests
Re: DS [#permalink] New post 18 Oct 2013, 02:45
Bunuel wrote:
anushapolavarapu wrote:
Hi fluke,

what about the combination {1,4,7}. even this satisfies the 2 conditions right.
1+4+7=12(x<y<z) and
1*4*7=28 which is < 36


So, I think answer should be E. Can you please help.


Welcome to GMAT Club. Below is an answer to your doubt.

The case when x=1, y=4, and z=7 does not satisfy the first statement, which says that z-x\leq{5} (Zelda has no more than 5 hats more than Xander). Also notice that there are some cases missing for (1) and (2) in fluke's solution.

Complete solution:

Xander, Yolanda, and Zelda each have at least one hat. Zelda has more hats than Yolanda, who has more than Xander. Together, the total number of hats the three people have is 12. How many hats does Yolanda have?

Given: x<y<z and x+y+z=12. Question: y=?

Now, only following 7 cases are possible;

X-Y-Z
1-2-9
1-3-8
1-4-7
1-5-6
2-3-7
2-4-6
3-4-5

(1) Zelda has no more than 5 hats more than Xander --> z-x\leq{5} --> first 3 cases are out and only following cases are left: {1, 5, 6}, {2, 3, 7}, {2, 4, 6}, and {3, 4, 5}. Not sufficient.

(2) The product of the numbers of hats that Xander, Yolanda, and Zelda have is less than 36 --> last 3 cases are out and only following cases are left: {1, 2, 9}, {1, 3, 8}, {1, 4, 7}, and {1, 5, 6}. Not sufficient.

(1)+(2) There is only one case common for (1) and (2): {1, 5, 6}, so z=6. Sufficient.

Answer: C.

Hope it's clear.


Yes, It was slightly time consuming question.
_________________

Like my post Send me a Kudos :) It is a Good manner.

Manager
Manager
avatar
Status: Do till 740 :)
Joined: 13 Jun 2011
Posts: 104
Concentration: Strategy, General Management
GMAT 1: 460 Q35 V20
GPA: 3.6
WE: Consulting (Computer Software)
Followers: 0

Kudos [?]: 5 [0], given: 18

GMAT ToolKit User
Re: Xander, Yolanda, and Zelda each have at least one hat. Zelda [#permalink] New post 21 Aug 2014, 04:52
Hi Bunuel,
I took 3 minutes to solve this problem.I took time to list down all the values XYZ with both constraints ie , XYZ <36 and X+Y+Z=12. how can i speed up in solving such problems? Is there a better way and while listing I get tensed too as i might miss some cases.

Kindly advise
Intern
Intern
avatar
Joined: 07 Mar 2014
Posts: 1
Followers: 0

Kudos [?]: 0 [0], given: 0

Re: Xander, Yolanda, and Zelda each have at least one hat. Zelda [#permalink] New post 21 Aug 2014, 10:09
Bunuel wrote:
aalba005 wrote:
anushapolavarapu wrote:
Hi fluke,

what about the combination {1,4,7}. even this satisfies the 2 conditions right.
1+4+7=12(x<y<z) and
1*4*7=28 which is < 36


So, I think answer should be E. Can you please help.


{1,4,7}. Z has more than 5 hats than X does. Again great explanation above.

Do you suggest during these type of questions to spend time writing out all combination possibilities at the start?


It depends how many possible combinations are there. Luckily there are only 7 for this question, so it's not hard to write them all down. In this case everything will be in front of you so you won't miss any case while solving.

What do you suggest if we weren't able to write down all possible answers ?!
For this particular question...
Re: Xander, Yolanda, and Zelda each have at least one hat. Zelda   [#permalink] 21 Aug 2014, 10:09
    Similar topics Author Replies Last post
Similar
Topics:
2 Experts publish their posts in the topic Xavier, Yvonne, and Zelda each try independently to solve a redbeanaddict 4 19 Jun 2008, 23:58
2 Experts publish their posts in the topic Zelda: Dr. Ladlow, a research psychologist, has convincingly nevergiveup 21 14 Nov 2007, 11:53
Questions 100-101 Zelda: Dr. Ladlow, a research jet1445 3 24 May 2007, 09:16
Zelda: Dr. Ladlow, a research psychologist, has convincingly rahulraao 3 13 Oct 2005, 17:31
Zelda: Dr. Ladlow, a research psychologist, has convincingly chunjuwu 7 09 Sep 2004, 06:53
Display posts from previous: Sort by

Xander, Yolanda, and Zelda each have at least one hat. Zelda

  Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.