|
Author |
Message |
|
TAGS:
|
|
|
Intern
Joined: 23 Aug 2011
Posts: 47
Followers: 0
Kudos [?]:
2
[1] , given: 4
|
Xander, Yolanda, and Zelda each have at least one hat. Zelda [#permalink]
 07 Oct 2011, 22:23
1
This post received
KUDOS
Question Stats:
61% (01:53) correct
38% (02:21) wrong based on 0 sessions
Xander, Yolanda, and Zelda each have at least one hat. Zelda has more hats than Yolanda, who has more than Xander. Together, the total number of hats the three people have is 12. How many hats does Yolanda have? (1) Zelda has no more than 5 hats more than Xander. (2) The product of the numbers of hats that Xander, Yolanda, and Zelda have is less than 36.
|
|
|
|
|
|
|
Math Forum Moderator
Joined: 20 Dec 2010
Posts: 2100
Followers: 108
Kudos [?]:
654
[1] , given: 376
|
1
This post received
KUDOS
kkalyan wrote: Xander, Yolanda, and Zelda each have at least one hat. Zelda has more hats than Yolanda, who has more than Xander. Together, the total number of hats the three people have is 12. How many hats does Yolanda have?
1. Zelda has no more than 5 hats more than Xander.
2. The product of the numbers of hats that Xander, Yolanda, and Zelda have is less than 36. kkalyan: Please tag the source correctly. It is a Manhattan GMAT question, not a GMAT Prep question. Also, please try to give a unique name for the subject. MGMAT DS: Hats owned by Xander, Yolanda, and Zelda Z>Y>X Z+Y+X=12 1) Z-X<=5 1, 5, 6 2, 4, 6 Not Sufficient. 2) X.Y.Z<36 1, 5, 6 1, 2, 9 Not Sufficient. Combined; {1, 5, 6} Y=5 Ans: "C"
_________________
~fluke
Find out what's new at GMAT Club - latest features and updates
|
|
|
|
|
|
Intern
Joined: 14 Oct 2011
Posts: 1
Followers: 0
Kudos [?]:
0
[0], given: 19
|
Hi fluke,
what about the combination {1,4,7}. even this satisfies the 2 conditions right.
1+4+7=12(x<y<z) and
1*4*7=28 which is < 36
So, I think answer should be E. Can you please help.
|
|
|
|
|
|
GMAT Club team member
Joined: 02 Sep 2009
Posts: 11506
Followers: 1791
Kudos [?]:
9526
[0], given: 826
|
anushapolavarapu wrote: Hi fluke,
what about the combination {1,4,7}. even this satisfies the 2 conditions right.
1+4+7=12(x<y<z) and
1*4*7=28 which is < 36
So, I think answer should be E. Can you please help. Welcome to GMAT Club. Below is an answer to your doubt. The case when x=1, y=4, and z=7 does not satisfy the first statement, which says that z-x\leq{5} (Zelda has no more than 5 hats more than Xander). Also notice that there are some cases missing for (1) and (2) in fluke's solution. Complete solution: Xander, Yolanda, and Zelda each have at least one hat. Zelda has more hats than Yolanda, who has more than Xander. Together, the total number of hats the three people have is 12. How many hats does Yolanda have?Given: x<y<z and x+y+z=12. Question: y=? Now, only following 7 cases are possible; X-Y-Z 1-2-9 1-3-8 1-4-7 1-5-6 2-3-7 2-4-6 3-4-5 (1) Zelda has no more than 5 hats more than Xander --> z-x\leq{5} --> first 3 cases are out and only following cases are left: {1, 5, 6}, {2, 3, 7}, {2, 4, 6}, and {3, 4, 5}. Not sufficient. (2) The product of the numbers of hats that Xander, Yolanda, and Zelda have is less than 36 --> last 3 cases are out and only following cases are left: {1, 2, 9}, {1, 3, 8}, {1, 4, 7}, and {1, 5, 6}. Not sufficient. (1)+(2) There is only one case common for (1) and (2): {1, 5, 6}, so z=6. Sufficient. Answer: C. Hope it's clear.
_________________
PLEASE READ AND FOLLOW: 11 Rules for Posting!!!
RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory
COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. NEW!!!
DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set. NEW!!!
What are GMAT Club Tests?
25 extra-hard Quant Tests
Find out what's new at GMAT Club - latest features and updates
|
|
|
|
|
|
Manager
Joined: 01 Apr 2010
Posts: 205
Followers: 1
Kudos [?]:
11
[0], given: 4
|
anushapolavarapu wrote: Hi fluke,
what about the combination {1,4,7}. even this satisfies the 2 conditions right.
1+4+7=12(x<y<z) and
1*4*7=28 which is < 36
So, I think answer should be E. Can you please help. {1,4,7}. Z has more than 5 hats than X does. Again great explanation above. Do you suggest during these type of questions to spend time writing out all combination possibilities at the start?
|
|
|
|
|
|
GMAT Club team member
Joined: 02 Sep 2009
Posts: 11506
Followers: 1791
Kudos [?]:
9526
[0], given: 826
|
Xander, Yolanda, and Zelda each have at least one hat. Zelda [#permalink]
23 Apr 2012, 10:37
aalba005 wrote: anushapolavarapu wrote: Hi fluke,
what about the combination {1,4,7}. even this satisfies the 2 conditions right.
1+4+7=12(x<y<z) and
1*4*7=28 which is < 36
So, I think answer should be E. Can you please help. {1,4,7}. Z has more than 5 hats than X does. Again great explanation above. Do you suggest during these type of questions to spend time writing out all combination possibilities at the start? It depends how many possible combinations are there. Luckily there are only 7 for this question, so it's not hard to write them all down. In this case everything will be in front of you so you won't miss any case while solving.
_________________
PLEASE READ AND FOLLOW: 11 Rules for Posting!!!
RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory
COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. NEW!!!
DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set. NEW!!!
What are GMAT Club Tests?
25 extra-hard Quant Tests
Find out what's new at GMAT Club - latest features and updates
|
|
|
|
|
|
|
Xander, Yolanda, and Zelda each have at least one hat. Zelda
[#permalink]
23 Apr 2012, 10:37
|
|
|
|
|
|
|
|
|
Similar topics |
Author |
Replies |
Last post |
|
Similar
Topics:
|
 |
|
|
Zelda: Dr. Ladlow, a research psychologist, has convincingly
|
anandnk |
6 |
29 Dec 2003, 09:59 |
 |
|
|
Zelda: Dr. Ladlow, a research psychologist, has convincingly
|
aspire |
10 |
12 Apr 2004, 13:27 |
|
|
|
|
Zelda: Dr. Ladlow, a research psychologist, has convincingly
|
chunjuwu |
9 |
09 Sep 2004, 07:53 |
|
|
|
|
Zelda: Dr. Ladlow, a research psychologist, has convincingly
|
rahulraao |
3 |
13 Oct 2005, 18:31 |
|
|
|
 |
Xavier, Yvonne, and Zelda each try independently to solve a
|
redbeanaddict |
4 |
20 Jun 2008, 00:58 |
|
|
|
|
|
|
close
