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# XY=1 What is the value of /

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XY=1 What is the value of / [#permalink]

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09 Jul 2006, 16:39
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

XY=1
What is the value of [2^(x+y)^2]/[2^(x-y)^2]?
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09 Jul 2006, 18:19
16

[2^(x+y)^2]/[2^(x-y)^2]
= 2^[(x+y)^2 - (x-y)^2]
= 2^(x^2+y^2+2xy-x^2-y^2+2xy)
= 2^(4xy)
= 2^4 = 16
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SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

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10 Jul 2006, 15:44
shehreenquayyum wrote:
XY=1
What is the value of [2^(x+y)^2]/[2^(x-y)^2]?

remember that if the base is the same and the exponents are different, all you have to do is subtract the top exponent - the bottom exponent. Leave the base unit. As shown by ps_dahiya....
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10 Jul 2006, 16:22
Using (x+y)^2 - (x-y)^2 = 4xy

Solution is : 2^4xy as xy = 1 => 2^4 = 16
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10 Jul 2006, 19:00
Thanks guys...much appreciated!
10 Jul 2006, 19:00
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