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Manager
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(See attached file for question)
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problem3.png [ 24.68 KiB | Viewed 238 times ]
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SVP
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from i, m = -ve. the line can pass through (a, b) = (2, 1), (1, 2) (-2, -1), (-1, 2), (2, -1) and so on.
From ii, b>a. (a,b) could be any values for example (1, 2) (-2, -1)
E. i donot see it is C.
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Manager
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I thought that a negative slope meant that the line had to run (for lack of a better term) from Northwest to Southeast - always down and to the right? Is that incorrect?
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Senior Manager
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HIMALAYA wrote: from i, m = -ve. the line can pass through (a, b) = (2, 1), (1, 2) (-2, -1), (-1, 2), (2, -1) and so on.
From ii, b>a. (a,b) could be any values for example (1, 2) (-2, -1)
E. i donot see it is C.
C is correct. taking both statements we can determine that the any point on the line is either in fourth or 2nd quadrant. with statement 2 we can locate the point in fourth quad with -ve X and +ve Y
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old_dream_1976 wrote: HIMALAYA wrote: from i, m = -ve. the line can pass through (a, b) = (2, 1), (1, 2) (-2, -1), (-1, 2), (2, -1) and so on.
From ii, b>a. (a,b) could be any values for example (1, 2) (-2, -1)
E. i donot see it is C. C is correct. taking both statements we can determine that the any point on the line is either in fourth or 2nd quadrant. with statement 2 we can locate the point in fourth quad with -ve X and +ve Y oohhhhhhh thats correct.
the line passes through orgin to a,b.
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VP
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I will take E here.
From 1) Line k is of the form y = -mx+c (c being the y intercept; See attached picture)
From 2) a < b
=> b = -ma + c
Depending on the value of c, the line pass through different quandrant (See attached picture)
HTH.
Attachments
line.GIF [ 3.2 KiB | Viewed 210 times ]
_________________
"To dream anything that you want to dream, that is the beauty of the human mind. To do anything that you want to do, that is the strength of the human will. To trust yourself, to test your limits, that is the courage to succeed."
- Bernard Edmonds
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C it is.
the slope of the line = (b-0)/(a -0)= b/a
from 1, b/a < 0
from 2, we have a<b
Combine two statements, it must be that: a< 0 <b
--> b is positive --> suff
Last edited by laxieqv on 02 Jan 2006, 21:27, edited 2 times in total.
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Manager
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giddi77
Remember the line passes thru the origin and therefore your figure is incorrect.
The correct answer is C. The point (a,b) is in the IInd quadrant, where the y-axis -point b- is positive.
spiderman_xx
giddi77 wrote: I will take E here.
From 1) Line k is of the form y = -mx+c (c being the y intercept; See attached picture)
From 2) a < b
=> b = -ma + c
Depending on the value of c, the line pass through different quandrant (See attached picture)
HTH.
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VP
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laxieqv wrote: C it is.
the slope of the line = (b-0)/(a -0)= b/a
from 1, b/a < 0
from 2, we have a<b
Combine two statements, it must be that: a<0<b --> b is positive --> suff
laxie you are right, I missed the passing through the origin part. Thanks for the explanation.
_________________
"To dream anything that you want to dream, that is the beauty of the human mind. To do anything that you want to do, that is the strength of the human will. To trust yourself, to test your limits, that is the courage to succeed."
- Bernard Edmonds
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SVP
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giddi77 wrote: laxieqv wrote: C it is.
the slope of the line = (b-0)/(a -0)= b/a
from 1, b/a < 0
from 2, we have a<b
Combine two statements, it must be that: a<0<b --> b is positive --> suff laxie you are right, I missed the passing through the origin part. Thanks for the explanation. The forum has technical errors, I typed a < 0 < b and it turns " a<0 b " 
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