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# |xy| > x^2y^2

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Manager
Joined: 25 Jul 2012
Posts: 80
Location: United States
Followers: 0

Kudos [?]: 8 [0], given: 137

|xy| > x^2y^2 [#permalink]  17 Aug 2013, 11:51
00:00

Difficulty:

35% (medium)

Question Stats:

57% (02:02) correct 42% (01:08) wrong based on 42 sessions
|xy| > x^2y^2 ?

(1) 0 < x^2 < 1/4
(2) 0 < y^2 < 1/9

Source: GMAT Prep Question Pack 1
Difficulty: Medium

--------------------
[Reveal] Spoiler:
Can someone please explain what to do with |xy| > x^2y^2 before we look into the equations?

I got |xy| > (xy)^2 but I didn't know how to interpret the inequality from here. Thanks in advance
[Reveal] Spoiler: OA

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Director
Joined: 14 Dec 2012
Posts: 836
Location: India
Concentration: Finance, Real Estate
GMAT 1: 640 Q49 V29
GMAT 2: 670 Q50 V29
GMAT 3: 620 Q49 V26
GMAT 4: 700 Q50 V34
GPA: 3.6
Followers: 31

Kudos [?]: 467 [1] , given: 196

Re: |xy| > x^2y^2 [#permalink]  17 Aug 2013, 12:01
1
KUDOS
DelSingh wrote:
|xy| > x^2y^2 ?

1) 0 < x^2 < 1/4

2) 0 < y^2 < 1/9

IMO C

|xy| > x^2y^2
since both sides are positive square both sides
(xy)^2 > (xy)^4
(xy)^2((xy)^2-1)<0
since (xy)^2>0 therefore (xy)^2-1<0
(xy)^2<1
or -1<xy<1
......so finally this is question.

finally you need both x and y to come to conclusion

STATEMENT 1==>ONLY X HENCE INSUFFICIENT.
0 < x^2 < 1/4
-1/2<x<1/2

STATEMENT 2 ==>ONLY Y HENCE INSUFFICIENT
0 < y^2 < 1/9
-1/3<y<1/3
now combining both clearly -1<xy<1
hence C

HOPE IT HELPS
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Last edited by blueseas on 17 Aug 2013, 14:16, edited 1 time in total.
Manager
Joined: 04 Apr 2013
Posts: 149
Followers: 1

Kudos [?]: 19 [0], given: 30

Re: |xy| > x^2y^2 [#permalink]  17 Aug 2013, 13:45
blueseas wrote:
DelSingh wrote:
|xy| > x^2y^2 ?

1) 0 < x^2 < 1/4

2) 0 < y^2 < 1/9

|xy| > x^2y^2
since both sides are positive square both sides
(xy)^2 > (xy)^4
(xy)^2((xy)^2-1)<0
since (xy)^2>0 therefore (xy)^2-1<0
(xy)^2<1
......so finally this is question.

finally you need both x and y to come to conclusion

STATEMENT 1==>ONLY X HENCE INSUFFICIENT.
STATEMENT 2 ==>ONLY Y HENCE INSUFFICIENT
hence D

HOPE IT HELPS

If both are insufficient OA is either C or E. Could you please elaborate?

for me the OA is C

Case 1: -> -1/2 < x < 1/2 and x <> 0

we dont know if |xy|>x^2y^2 as we dont know about Y

case 2; -> -1/3 < y < 1/3 and y <> 0

we dont know if |xy|>x^2y^2 as we dont know about X

Combining both

for any values of x & Y , |xy| > x^2y^2
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MGMAT1 - 540 ( Trying to improve )

Director
Joined: 14 Dec 2012
Posts: 836
Location: India
Concentration: Finance, Real Estate
GMAT 1: 640 Q49 V29
GMAT 2: 670 Q50 V29
GMAT 3: 620 Q49 V26
GMAT 4: 700 Q50 V34
GPA: 3.6
Followers: 31

Kudos [?]: 467 [1] , given: 196

Re: |xy| > x^2y^2 [#permalink]  17 Aug 2013, 14:17
1
KUDOS

If both are insufficient OA is either C or E. Could you please elaborate?

for me the OA is C

THANKS .
that was mistake.
_________________

When you want to succeed as bad as you want to breathe ...then you will be successfull....

GIVE VALUE TO OFFICIAL QUESTIONS...

learn AWA writing techniques while watching video : http://www.gmatprepnow.com/module/gmat- ... assessment

Re: |xy| > x^2y^2   [#permalink] 17 Aug 2013, 14:17
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