blueseas wrote:

DelSingh wrote:

|xy| > x^2y^2 ?

1) 0 < x^2 < 1/4

2) 0 < y^2 < 1/9

|xy| > x^2y^2since both sides are positive square both sides

(xy)^2 > (xy)^4(xy)^2((xy)^2-1)<0since

(xy)^2>0 therefore

(xy)^2-1<0(xy)^2<1......so finally this is question.

finally you need both x and y to come to conclusion

STATEMENT 1==>ONLY

X HENCE INSUFFICIENT.

STATEMENT 2 ==>ONLY

Y HENCE INSUFFICIENT

hence

DHOPE IT HELPS

If both are insufficient OA is either C or E. Could you please elaborate?

for me the OA is C

Case 1: -> -1/2 < x < 1/2 and x <> 0

we dont know if |xy|>x^2y^2 as we dont know about Y

case 2; -> -1/3 < y < 1/3 and y <> 0

we dont know if |xy|>x^2y^2 as we dont know about X

Combining both

for any values of x & Y , |xy| > x^2y^2

_________________

Maadhu

MGMAT1 - 540 ( Trying to improve )