xy>z? 1) xyz=1 2) xyz^2>1 pls, provide ur explanation

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xy>z? 1) xyz=1 2) xyz^2>1 pls, provide ur explanation [#permalink]

23 Apr 2006, 04:15

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xy>z?
1) xyz=1
2) xyz^2>1

pls, provide ur explanation.
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23 Apr 2006, 04:25

(1) or (2) alone are clearly not sufficient.

(1) xyz = 1
(2) xyz^2 > 1

Taken together:
xyz^2 - xyz > 0
xyz (z-1) > 0
1 * (z-1) > 0
z > 1

So xy < 1 and xy < z.

So it's C.

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23 Apr 2006, 04:35

Nothing more to add.

C should be

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bad.... [#permalink]

23 Apr 2006, 07:24

ccax wrote:

(1) or (2) alone are clearly not sufficient.

(1) xyz = 1
(2) xyz^2 > 1

Taken together:
xyz^2 - xyz > 0
xyz (z-1) > 0
1 * (z-1) > 0
z > 1

So xy < 1 and xy < z.

So it's C.

I'm very sad to be in a misconception.

but, as you said xy<1, and z >1
then, xy<1<z => xy < z (N.S.)

how is that? pls enlighten myself.
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Re: bad.... [#permalink]

23 Apr 2006, 07:44

foolbox wrote:

how is that? pls enlighten myself.

How is what? Which step didn't you understand?

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... [#permalink]

23 Apr 2006, 08:48

shouldn't the question be xy<z, instead of xy>z?

cause you figured out that xy<1, and z>1 => xy<z

god... know what i mean? :oops:

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Re: ... [#permalink]

23 Apr 2006, 08:54

foolbox wrote:

shouldn't the question be xy<z, instead of xy>z?

Well it was you who wrote the question

But if I say that xy<z, then it means that the answer to the
question whether xy>z is no.

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24 Apr 2006, 07:22

Yeah I think I got question wrong

Friend, Can we take of putting brackets in future ? I thought xyz^2 to be (xyz)^2 and got answer E

May be its just me ....

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29 Apr 2006, 00:38

Great explanation, should be C
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[#permalink] 29 Apr 2006, 00:38

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xy>z? 1) xyz=1 2) xyz^2>1 pls, provide ur explanation

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xy>z? 1) xyz=1 2) xyz^2>1 pls, provide ur explanation

xy>z? 1) xyz=1 2) xyz^2>1 pls, provide ur explanation

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