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xy>z? 1) xyz=1 2) xyz^2>1 pls, provide ur explanation

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xy>z? 1) xyz=1 2) xyz^2>1 pls, provide ur explanation [#permalink] New post 23 Apr 2006, 03:15
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xy>z?
1) xyz=1
2) xyz^2>1

pls, provide ur explanation.
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 [#permalink] New post 23 Apr 2006, 03:25
(1) or (2) alone are clearly not sufficient.

(1) xyz = 1
(2) xyz^2 > 1

Taken together:
xyz^2 - xyz > 0
xyz (z-1) > 0
1 * (z-1) > 0
z > 1

So xy < 1 and xy < z.

So it's C.
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 [#permalink] New post 23 Apr 2006, 03:35
Nothing more to add.

C should be
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bad.... [#permalink] New post 23 Apr 2006, 06:24
ccax wrote:
(1) or (2) alone are clearly not sufficient.

(1) xyz = 1
(2) xyz^2 > 1

Taken together:
xyz^2 - xyz > 0
xyz (z-1) > 0
1 * (z-1) > 0
z > 1

So xy < 1 and xy < z.

So it's C.


I'm very sad to be in a misconception.

but, as you said xy<1, and z >1
then, xy<1<z => xy < z (N.S.)

how is that? pls enlighten myself.
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Re: bad.... [#permalink] New post 23 Apr 2006, 06:44
foolbox wrote:
how is that? pls enlighten myself.


How is what? Which step didn't you understand?
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... [#permalink] New post 23 Apr 2006, 07:48
shouldn't the question be xy<z, instead of xy>z?

cause you figured out that xy<1, and z>1 => xy<z

god... know what i mean? :oops:
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Re: ... [#permalink] New post 23 Apr 2006, 07:54
foolbox wrote:
shouldn't the question be xy<z, instead of xy>z?


Well it was you who wrote the question :P

But if I say that xy<z, then it means that the answer to the
question whether xy>z is no.
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 [#permalink] New post 24 Apr 2006, 06:22
Yeah I think I got question wrong

Friend, Can we take of putting brackets in future ? I thought xyz^2 to be (xyz)^2 and got answer E :)

May be its just me ....
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 [#permalink] New post 28 Apr 2006, 23:38
Great explanation, should be C
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  [#permalink] 28 Apr 2006, 23:38
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