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xyz not equal to 0 is x(y+z)=0? 1) |y+z|= |y|+ |z| 2) |x+y|=

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Senior Manager
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xyz not equal to 0 is x(y+z)=0? 1) |y+z|= |y|+ |z| 2) |x+y|= [#permalink] New post 02 Sep 2006, 00:42
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xyz not equal to 0 is x(y+z)=0?

1) |y+z|= |y|+ |z|
2) |x+y|= |x| + |y|


Shouldnt this be A?
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Re: absolute value DS [#permalink] New post 02 Sep 2006, 03:12
apollo168 wrote:
xyz not equal to 0 is x(y+z)=0?

1) |y+z|= |y|+ |z|
2) |x+y|= |x| + |y|


Shouldnt this be A?


Can't be A, because we have no info about x.
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Re: absolute value DS [#permalink] New post 02 Sep 2006, 03:19
GMATT73 wrote:
apollo168 wrote:
xyz not equal to 0 is x(y+z)=0?

1) |y+z|= |y|+ |z|
2) |x+y|= |x| + |y|


Shouldnt this be A?


Can't be A, because we have no info about x.


Yeah but since from the question stem x can't equal zero, and from statement 1 y and z have the same sign, the value of x shouldn't matter right? The expression can't be equal to zero?
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Re: absolute value DS [#permalink] New post 02 Sep 2006, 03:49
apollo168 wrote:
GMATT73 wrote:
apollo168 wrote:
xyz not equal to 0 is x(y+z)=0?

1) |y+z|= |y|+ |z|
2) |x+y|= |x| + |y|


Shouldnt this be A?


Can't be A, because we have no info about x.


Yeah but since from the question stem x can't equal zero, and from statement 1 y and z have the same sign, the value of x shouldn't matter right? The expression can't be equal to zero?


I take that back Apollo. You are right, x can`t be 0. In (A), even if they are the same or different integers, then we can definitively answer this question ---No.

(A)
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 [#permalink] New post 02 Sep 2006, 04:12
Thanks for confirming. The OA that is given in these question sets can be dubious sometimes.
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 [#permalink] New post 02 Sep 2006, 08:31
xyz not equal to 0 is x(y+z)=0?

1) |y+z|= |y|+ |z|
2) |x+y|= |x| + |y|


Question stem x not = 0 therfore the question is asking whether y and z have the same value with different signs or not.

from one it informs us with the following

that the distance from y to z on the number lines is equal to each individual distance (y,z) from zero added together ,this could only be true if they are at two different sides of zero....suff

from two

we ve got no info about Z ...insuff


Another vote for A
  [#permalink] 02 Sep 2006, 08:31
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