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y>=0, what is the value of X? 1) |x-3|>=y 2)

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y>=0, what is the value of X? 1) |x-3|>=y 2) [#permalink] New post 30 Nov 2008, 10:21
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y>=0, what is the value of X?

1) |x-3|>=y
2) |x-3|=<-y
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Re: DS inequality [#permalink] New post 30 Nov 2008, 11:07
Rice wrote:
y>=0, what is the value of X?

1) |x-3|>=y
2) |x-3|=<-y



i get B

we know that modulus is alway positive, so at most RHS is 0..we know y is Positive or 0..the only way this can hold is if y=0
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Re: DS inequality [#permalink] New post 30 Nov 2008, 20:37
I get E

If you simply both the statements are same
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Re: DS inequality [#permalink] New post 30 Nov 2008, 22:25
Agree with B.

The key here is to understand that since y>=0, -y will be negative
and that absoulte value can not be -ve.
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Re: DS inequality [#permalink] New post 03 Dec 2008, 19:02
I understand that Y needs to be equal to 0 but I'm not sure why the answer is B only. Would somebody please explain further? Is it because the - in front of y tells us that y must equal 0 while A doesn't provide that information? I guess it is....
Re: DS inequality   [#permalink] 03 Dec 2008, 19:02
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