I got C

If Y intersects x axis then we can say

0 = a(x-b)^2 + P

i.e (x-b)^2 = -P/a

there are two solutions to this equation

x = b+ SQRT(-P/a).............Eq1

OR

x = b-SQRT(-P/a)...............Eq2

For Y to intersect with x-axis x must be a real number.

St1: a<0. If P is -ve then both equations yield x = imaginary number. If P is +ve then both equations yield x = real number -----INSUFF

St2: P>0 If a is +ve then both equations yield x = imaginary number. If a is -ve then both equations yield x = real number -----INSUFF

Both statements together yield x = real number

Am I right laxie???

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SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008