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Y and Z are both positive numbers less than 1 . Is Y > Z

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Y and Z are both positive numbers less than 1 . Is Y > Z [#permalink] New post 15 May 2011, 13:57
00:00
A
B
C
D
E

Difficulty:

  75% (hard)

Question Stats:

47% (02:52) correct 53% (01:46) wrong based on 15 sessions
Y and Z are both positive numbers less than 1. Is Y > Z ?

(1) The hundredths digit of Y is greater than the tenths digit of Z and less than the hundredths digit of Z.
(2) The thousandths digit of Y is greater than the hundredths digit of Y and less than the tenths digit of Y.
[Reveal] Spoiler: OA
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Re: Rounding of decimals [#permalink] New post 15 May 2011, 17:23
1) Insufficient
Let Y =0.x2 where x is some digit.
Z = 0.14
In this case we dont know the tenth digit of X. Hence insufficient

2) Insufficient
Let Y = 0.312. This does not tell us anything about Z

1) + 2) Sufficient The answer is YES

Let Y = 0.524
Z = 0.13x

Hence C

fluke wrote:
Y and Z are both positive numbers less than 1. Is Y > Z ?

(1) The hundredths digit of Y is greater than the tenths digit of Z and less than the hundredths digit of Z.
(2) The thousandths digit of Y is greater than the hundredths digit of Y and less than the tenths digit of Y.
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Re: Rounding of decimals [#permalink] New post 15 May 2011, 19:03
To find the answer it is imp to know the the relation between tenths digit of Y & Z.
from both statement together we can get it.
Hence =>C
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Re: Rounding of decimals [#permalink] New post 15 May 2011, 19:17
a Y = 0.55 | 0.37 Z = 0.46 gives different results. Not sufficient.

b only Y and no X, no sufficient.


a+b Y = 0.645 | 0.325 X = 0.36 | 0.13 both the cases Y> X.

C
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Re: Rounding of decimals [#permalink] New post 17 May 2011, 00:14
(1)

y= 0.25
z = 0.46

y = 0.25
z = 0.16

Insufficient

(2)
tenths digit of Y is greater than hunderd's digit
Insufficient as we don't know about z

(1) + (2)

Tenths digit of y is > tenths digit of z

So y > z

Answer - C
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Re: Rounding of decimals [#permalink] New post 12 Aug 2011, 21:16
Y = .abc

Z = .pqr

from statement 2: a > c > b

From statement 1:
b>P

from statement 1 a > b so a > p

there for Y is > Z
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Re: Rounding of decimals [#permalink] New post 20 Aug 2011, 04:36
+1 for C.

Let Y = 0.cde
Let Z = 0.rst

Statement I: d > r ; d < s : Insufficient as we need relationship between c and r.
Statement II: e> d;e < c : Insufficient as we need relationship between c and r.

I and II together : c > e > d > r => Y > Z. Hence C

Crick
Re: Rounding of decimals   [#permalink] 20 Aug 2011, 04:36
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Y and Z are both positive numbers less than 1 . Is Y > Z

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