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Senior Manager
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y is not zero, is (2^x/y)^x<1? 1). x>y 2). y< 0 [#permalink]
 27 Oct 2008, 05:31
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y is not zero, is (2^x/y)^x<1? 1). x>y 2). y< 0 Please explain your approach
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rampuria
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Manager
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(2^x/y)^x = (2^x)^x/(y)^x from (1) x > y --> x^x > y^x --> 2^x^x > y^x --> (2^x/y)^x > 1 and hence Sufficient (2) does not talk about x ..Not Suffcient Hence answer should be (A).
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kris
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i would go with B..
if y is negative then we have a fraction..
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CEO
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rampuria wrote: y is not zero, is (2^x/y)^x<1?
1). x>y
2). y< 0
Please explain your approach agree with B. (2^x/y)^x = 2^(x^2/y) 1) x > y : not sure about y, which could be -ve or +ve. Either is suff but we need to know y whether it is -ve or +ve. 2) y< 0 : y is -ve. suff. the power of 2 becomes -ve, yeilding a +vwe fraction value.
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Manager
Joined: 28 Jul 2004
Posts: 142
Location: Melbourne
Schools: Yale SOM, Tuck, Ross, IESE, HEC, Johnson, Booth
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GMAT TIGER wrote: rampuria wrote: y is not zero, is (2^x/y)^x<1?
1). x>y
2). y< 0
Please explain your approach agree with B. (2^x/y)^x = 2^(x^2/y) 1) x > y : not sure about y, which could be -ve or +ve. Either is suff but we need to know y whether it is -ve or +ve. 2) y< 0 : y is -ve. suff. the power of 2 becomes -ve, yeilding a +vwe fraction value. Oh.. I got the question wrong. I read it as 2^x is divided by y and complete thing raised ti power x. It looks like the stem is 2 raised to the power x/y and complete thing raised to power x.
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kris
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VP
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krishan wrote: GMAT TIGER wrote: rampuria wrote: y is not zero, is (2^x/y)^x<1?
1). x>y
2). y< 0
Please explain your approach agree with B. (2^x/y)^x = 2^(x^2/y) 1) x > y : not sure about y, which could be -ve or +ve. Either is suff but we need to know y whether it is -ve or +ve. 2) y< 0 : y is -ve. suff. the power of 2 becomes -ve, yeilding a +vwe fraction value. Oh.. I got the question wrong. I read it as 2^x is divided by y and complete thing raised ti power x. It looks like the stem is 2 raised to the power x/y and complete thing raised to power x. Yep! I was wondering whether the Q is ( 2 ^ (x/y) ) ^ x or ( ( 2 ^ x) / y ) ^ x
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