Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 23 Sep 2014, 10:34

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# y1 , y2 , y3 .... are all distinct integers and represent

Author Message
TAGS:
Manager
Joined: 22 Feb 2007
Posts: 165
Followers: 2

Kudos [?]: 9 [0], given: 0

y1 , y2 , y3 .... are all distinct integers and represent [#permalink]  15 Mar 2007, 23:55
1
This post was
BOOKMARKED
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 100% (01:46) wrong based on 8 sessions
y1 , y2 , y3 .... are all distinct integers and represent the entire set of integers. P is a non negative number such that
P = (x - y1 ) (x - y2 ) (x - y3 ) .... upto infinity, where x is an integer.

Which of the following value can x take so that p has the least value?
I. 0 II. 1 III. -1

(A) I only
(B) II only
(C) I and II only
(D) I and III only
(E) any of I, II or III
SVP
Joined: 01 May 2006
Posts: 1814
Followers: 8

Kudos [?]: 89 [0], given: 0

Direct (E)

All values of x provide P = 0 .... There is no maximum or minimum but only equaled values of P to 0
Director
Joined: 13 Dec 2006
Posts: 521
Location: Indonesia
Followers: 6

Kudos [?]: 95 [0], given: 0

I agree... infact for any integer its true, whenever Yn=X...

regards,

Amardeep
Manager
Joined: 22 Feb 2007
Posts: 165
Followers: 2

Kudos [?]: 9 [0], given: 0

I got it wrong though
Manager
Joined: 14 Apr 2010
Posts: 230
Followers: 2

Kudos [?]: 24 [0], given: 1

Re: PS [#permalink]  04 May 2010, 19:36
Hey,
I was going through this problem. Somehow, i could not understand the explanation provided. Please, help me through this.
Bibha
Manager
Joined: 05 Mar 2010
Posts: 220
Followers: 1

Kudos [?]: 23 [0], given: 8

Re: PS [#permalink]  05 May 2010, 03:07
GMAThopeful wrote:
y1 , y2 , y3 .... are all distinct integers and represent the entire set of integers. P is a non negative number such that
P = (x - y1 ) (x - y2 ) (x - y3 ) .... upto infinity, where x is an integer.

Which of the following value can x take so that p has the least value?
I. 0 II. 1 III. -1

(A) I only
(B) II only
(C) I and II only
(D) I and III only
(E) any of I, II or III

IMO E
here's my explanation-

questions say "y1 , y2 , y3 .... are all distinct integers and represent the entire set of integers"
so one is a negative integer, one is positive and third zero
Now the least value of P will be zero because it goes upto infinity. Put in the values of y1, y2, y3 to make p=0

All three satisfies the condition.
Correct me if i am wrong
_________________

Success is my Destiny

Senior Manager
Joined: 12 Jan 2010
Posts: 258
Schools: DukeTuck,Kelogg,Darden
Followers: 6

Kudos [?]: 42 [1] , given: 28

Re: PS [#permalink]  05 May 2010, 10:03
1
KUDOS
GMAThopeful wrote:
y1 , y2 , y3 .... are all distinct integers and represent the entire set of integers. P is a non negative number such that
P = (x - y1 ) (x - y2 ) (x - y3 ) .... upto infinity, where x is an integer.

Which of the following value can x take so that p has the least value?
I. 0 II. 1 III. -1

(A) I only
(B) II only
(C) I and II only
(D) I and III only
(E) any of I, II or III

Its E.

since y1,y2 ...yn are disticnt integers they will be equal to 0,-1 and 1 at some point or the other and at that point

x = 0 will give (0-0) so P=0
x=1 will be 0 when y = -1
x =-1 will be 0 at y = 1

so no matter what value of x we take the value of P will be 0.
_________________

Run towards the things that make you uncomfortable daily. The greatest risk is not taking risks
http://gmatclub.com/forum/from-690-to-730-q50-v38-97356.html

Director
Joined: 24 Aug 2007
Posts: 956
WE 1: 3.5 yrs IT
WE 2: 2.5 yrs Retail chain
Followers: 54

Kudos [?]: 713 [1] , given: 40

Re: PS [#permalink]  05 May 2010, 10:31
1
KUDOS
It's E but it is not mandatory that the value of P = 0 in all the cases.

Let's see how: say y1, y2, y3,... = -4, -2, 0, 2, 4

I. x=0 >>> P = (0+4)(0+2)(0+0)(0-2)(0-4)... = 0
II. 1 >>> P = (1+4)(1+2)(1+0)(1-2)(1-4)... = Non-zero
III. -1 >>> P = (-1+4)(-1+2)(-1+0)(-1-2)(-1-4)... = Non-zero

Hope this helps.

hardnstrong wrote:
GMAThopeful wrote:
y1 , y2 , y3 .... are all distinct integers and represent the entire set of integers. P is a non negative number such that
P = (x - y1 ) (x - y2 ) (x - y3 ) .... upto infinity, where x is an integer.

Which of the following value can x take so that p has the least value?
I. 0 II. 1 III. -1

(A) I only
(B) II only
(C) I and II only
(D) I and III only
(E) any of I, II or III

IMO E
here's my explanation-

questions say "y1 , y2 , y3 .... are all distinct integers and represent the entire set of integers"
so one is a negative integer, one is positive and third zero
Now the least value of P will be zero because it goes upto infinity. Put in the values of y1, y2, y3 to make p=0

All three satisfies the condition.
Correct me if i am wrong

_________________

Tricky Quant problems: 50-tricky-questions-92834.html
Important Grammer Fundamentals: key-fundamentals-of-grammer-our-crucial-learnings-on-sc-93659.html

Manager
Joined: 05 Mar 2010
Posts: 220
Followers: 1

Kudos [?]: 23 [0], given: 8

Re: PS [#permalink]  07 May 2010, 04:44
ykaiim wrote:
It's E but it is not mandatory that the value of P = 0 in all the cases.

Let's see how: say y1, y2, y3,... = -4, -2, 0, 2, 4

I. x=0 >>> P = (0+4)(0+2)(0+0)(0-2)(0-4)... = 0
II. 1 >>> P = (1+4)(1+2)(1+0)(1-2)(1-4)... = Non-zero
III. -1 >>> P = (-1+4)(-1+2)(-1+0)(-1-2)(-1-4)... = Non-zero

Hope this helps.

hardnstrong wrote:
GMAThopeful wrote:
y1 , y2 , y3 .... are all distinct integers and represent the entire set of integers. P is a non negative number such that
P = (x - y1 ) (x - y2 ) (x - y3 ) .... upto infinity, where x is an integer.

Which of the following value can x take so that p has the least value?
I. 0 II. 1 III. -1

(A) I only
(B) II only
(C) I and II only
(D) I and III only
(E) any of I, II or III

IMO E
here's my explanation-

questions say "y1 , y2 , y3 .... are all distinct integers and represent the entire set of integers"
so one is a negative integer, one is positive and third zero
Now the least value of P will be zero because it goes upto infinity. Put in the values of y1, y2, y3 to make p=0

All three satisfies the condition.
Correct me if i am wrong

Question is asking for the least value of P , which can be 0 only(which is possible in this case) as P is a non negative number
if you find value of P as zero in one case and non zero in otherwise. that way you contradicts the correct answer that all three values satifies. Here we have to prove if all three conditions could satisfy it or not. Not necessarily true in all cases
You example shows that only one value satisfies. Hence changes the answer

Hope this helps
_________________

Success is my Destiny

Director
Joined: 24 Aug 2007
Posts: 956
WE 1: 3.5 yrs IT
WE 2: 2.5 yrs Retail chain
Followers: 54

Kudos [?]: 713 [0], given: 40

Re: PS [#permalink]  07 May 2010, 05:45
Agree. To become the least value, P is to be 0 or -ve.

I just took a sample to prove that it is not neccessary to have P = 0 as the only option. Since, the series is infinitly long so you can take as many values in the series.
_________________

Tricky Quant problems: 50-tricky-questions-92834.html
Important Grammer Fundamentals: key-fundamentals-of-grammer-our-crucial-learnings-on-sc-93659.html

Senior Manager
Joined: 19 Nov 2009
Posts: 329
Followers: 4

Kudos [?]: 60 [0], given: 44

Re: PS [#permalink]  08 May 2010, 22:34
great explanations !
_________________

"Success is going from failure to failure without a loss of enthusiam." - Winston Churchill

As vs Like - Check this link : http://www.grammar-quizzes.com/like-as.html.

Director
Joined: 24 Aug 2007
Posts: 956
WE 1: 3.5 yrs IT
WE 2: 2.5 yrs Retail chain
Followers: 54

Kudos [?]: 713 [0], given: 40

Re: PS [#permalink]  08 May 2010, 23:56
A few more things. It is not mentioned that:

1. Order is not mentioned that y1, y2, y3... can be concesutive numbers. So, this series can be >>> (-2, 0, 2, 4...), (-2, -1, 0, 1, 2...), (-5, -4, 0, 2, 10...)
2. P is non-negative, which means it can be 0 or a +ve number and moreover a limit on value of P is not mentioned.

So, my cases are correct.
_________________

Tricky Quant problems: 50-tricky-questions-92834.html
Important Grammer Fundamentals: key-fundamentals-of-grammer-our-crucial-learnings-on-sc-93659.html

Re: PS   [#permalink] 08 May 2010, 23:56
Similar topics Replies Last post
Similar
Topics:
2 If (y+3)(y-1)-(y-2)(y-1)=r(y-1), what is the value of y? 10 24 Aug 2011, 19:04
y1 , y2 , y3 .... are all distinct integers and represent 4 03 Oct 2008, 20:59
If (y+3)(y-1) (y-2)(y-1) = r(y-1), what is the value of y? 3 19 Jan 2008, 10:57
If (y+3)(y-1) (y-2)(y-1) = r(y-1), what is the value of y? 7 14 Jan 2008, 06:24
(y+3)(y-1) - (y-2)(y-1) = r(y-1) what is the value of y? (1) 5 05 Feb 2007, 07:42
Display posts from previous: Sort by