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Yesterday Diana spent a total of 240 minutes attending a

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Yesterday Diana spent a total of 240 minutes attending a [#permalink] New post 07 Sep 2010, 14:37
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Yesterday Diana spent a total of 240 minutes attending a training class, responding to E-mails, and talking on the phone. If she did no two of these three activities at the same time, how much time did she spend talking on the phone?

(1) Yesterday the amount of time that Diana spent attending the training class was 90 percent of the amount of time that she spent responding to E-mails.
(2) Yesterday the amount of time that Diana spent attending the training class was 60 percent of the total amount of time that she spent responding to E-mails and talking on the phone.
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Re: algebra [#permalink] New post 07 Sep 2010, 14:48
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Expert's post
mehdiov wrote:
Yesterday Diana spent a total of 240 minutes attending a training class, responding to E-
mails, and talking on the phone. If she did no two of these three activities at the same
time, how much time did she spend talking on the phone?
(1) Yesterday the amount of time that Diana spent attending the training class was
90 percent of the amount of time that she spent responding to E-mails.
(2) Yesterday the amount of time that Diana spent attending the training class was
60 percent of the total amount of time that she spent responding to E-mails and
talking on the phone.


Given: C+E+P=240, where C is th time she spent on training class, E is the time she spent on E-mail and P is the time she spent on phone. Question: P=?

(1) C=0.9E --> C+E+P=0.9E+E+P=1.9E+P=240. Not sufficient to calculate P (one equation, two variables).

(2) C=0.6(E+P) --> C+E+P=0.6(E+P)+E+P=1.6E+1.6P=240. Not sufficient to calculate P (one equation, two variables).

(1)+(2) 1.9E+P=240 and 1.6E+1.6P=240 --> we have two distinct linear equations with two variables hence we can calculate each of them. Sufficient.

Answer: C.
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Intern
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Joined: 01 Jul 2013
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Schools: LBS MIF '15
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Re: algebra [#permalink] New post 22 Oct 2013, 06:02
Bunuel wrote:
mehdiov wrote:
Yesterday Diana spent a total of 240 minutes attending a training class, responding to E-
mails, and talking on the phone. If she did no two of these three activities at the same
time, how much time did she spend talking on the phone?
(1) Yesterday the amount of time that Diana spent attending the training class was
90 percent of the amount of time that she spent responding to E-mails.
(2) Yesterday the amount of time that Diana spent attending the training class was
60 percent of the total amount of time that she spent responding to E-mails and
talking on the phone.


Given: C+E+P=240, where C is th time she spent on training class, E is the time she spent on E-mail and P is the time she spent on phone. Question: P=?

(1) C=0.9E --> C+E+P=0.9E+E+P=1.9E+P=240. Not sufficient to calculate P (one equation, two variables).

(2) C=0.6(E+P) --> C+E+P=0.6(E+P)+E+P=1.6E+1.6P=240. Not sufficient to calculate P (one equation, two variables).

(1)+(2) 1.9E+P=240 and 1.6E+1.6P=240 --> we have two distinct linear equations with two variables hence we can calculate each of them. Sufficient.

Answer: C.


Bunuel, for statement 2 we can rearrange to get E+P=240/1.6. If we have E+P, cant we plug this into C+E+P=240, which gives us C+(240/1.6)=240, which gives us C=240-(240/1.6)? Hence 2 would be sufficient as you rearrange to get P?
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Re: algebra [#permalink] New post 22 Oct 2013, 06:56
Expert's post
bulletpoint wrote:
Bunuel wrote:
mehdiov wrote:
Yesterday Diana spent a total of 240 minutes attending a training class, responding to E-
mails, and talking on the phone. If she did no two of these three activities at the same
time, how much time did she spend talking on the phone?
(1) Yesterday the amount of time that Diana spent attending the training class was
90 percent of the amount of time that she spent responding to E-mails.
(2) Yesterday the amount of time that Diana spent attending the training class was
60 percent of the total amount of time that she spent responding to E-mails and
talking on the phone.


Given: C+E+P=240, where C is th time she spent on training class, E is the time she spent on E-mail and P is the time she spent on phone. Question: P=?

(1) C=0.9E --> C+E+P=0.9E+E+P=1.9E+P=240. Not sufficient to calculate P (one equation, two variables).

(2) C=0.6(E+P) --> C+E+P=0.6(E+P)+E+P=1.6E+1.6P=240. Not sufficient to calculate P (one equation, two variables).

(1)+(2) 1.9E+P=240 and 1.6E+1.6P=240 --> we have two distinct linear equations with two variables hence we can calculate each of them. Sufficient.

Answer: C.


Bunuel, for statement 2 we can rearrange to get E+P=240/1.6. If we have E+P, cant we plug this into C+E+P=240, which gives us C+(240/1.6)=240, which gives us C=240-(240/1.6)? Hence 2 would be sufficient as you rearrange to get P?


Please show your work and get the value of P.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
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Get the best GMAT Prep Resources with GMAT Club Premium Membership

Re: algebra   [#permalink] 22 Oct 2013, 06:56
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