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Yesterday each of the 35 members of a certain task force

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Intern
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Joined: 14 Jun 2005
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Yesterday each of the 35 members of a certain task force [#permalink] New post 08 Oct 2005, 14:23
Yesterday each of the 35 members of a certain task force spent some time working on project P. Below are the number of hours and the number of members who spent that number of hours working on project P. What was the median number of hours that the members of the task force spent working on project P yesterday?

# of Employees ---- Hours spent

9---- 1
4---- 2
1---- 3
2---- 4
1---- 5
8---- 6
10--- 7
Director
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 [#permalink] New post 08 Oct 2005, 16:34
18th number in the sequence of hours (increasing) is the median. From the given frequency distribution, the 18th number, which is the median is 6
SVP
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Re: P/S - Median [#permalink] New post 08 Oct 2005, 16:46
total emplyoees= 35
median emplyoee= (35+1)/2 = 18th emplyoee.
median hour spent is the median emplyoee's hours spent=6 hours.
Current Student
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 [#permalink] New post 08 Oct 2005, 17:23
I get 8 :(

I just multipled number of employees by number of hours...

so here is the distribuition I get

3 5 8 8 9 48 70

8 looks like the median...
SVP
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 [#permalink] New post 08 Oct 2005, 19:17
fresinha12 wrote:
I get 8 :(
I just multipled number of employees by number of hours...
so here is the distribuition I get
3 5 8 8 9 48 70
8 looks like the median...

Median = [(n+1)/2]th value = [(35+1)/2]th value= 18th value, which is 6 hours.
Director
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 [#permalink] New post 08 Oct 2005, 19:36
HIMALAYA wrote:
fresinha12 wrote:
I get 8 :(
I just multipled number of employees by number of hours...
so here is the distribuition I get
3 5 8 8 9 48 70
8 looks like the median...

Median = [(n+1)/2]th value = [(35+1)/2]th value= 18th value, which is 6 hours.


Precisely. 6 is the median.
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Cheers, Rahul.

VP
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 [#permalink] New post 09 Oct 2005, 17:25
Does the formula work for even N numbers too?
Senior Manager
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 [#permalink] New post 09 Oct 2005, 19:23
For even numbers you need to take average of the 2 middle numbers as median.
  [#permalink] 09 Oct 2005, 19:23
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