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Yesterday each of the 35 members of a certain task force [#permalink]
21 Oct 2009, 07:56

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Difficulty:

55% (hard)

Question Stats:

56% (02:14) correct
44% (01:03) wrong based on 139 sessions

Attachment:

13996-medium.jpg [ 11.87 KiB | Viewed 5431 times ]

Yesterday each of the 35 members of a certain task force spent some time working on project P. The graph shows the number of hours and the number of members who spent that number of hours working on project P yesterday. What was the median number of hours that the members of the task force spent working on project P yesterday?

Re: 35 members of a certain task force [#permalink]
21 Oct 2009, 09:12

1

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Expert's post

mendelay wrote:

Attachment:

13996-medium.jpg

Yesterday each of the 35 members of a certain task force spent some time working on project P. The graph shows the number of hours and the number of members who spent that number of hours working on project P yesterday. What was the median number of hours that the members of the task force spent working on project P yesterday?

A. 2 B. 3 C. 4 D. 5 E. 6

We have set consisting of 35 terms (terms=number of members): 9+4+1+2+1+8+10=35. Median of a set, with odd number of terms, would be the middle term, so 18th term. Values of terms: 9 terms=1, 4 terms=2, 1 term=3, 2 terms=4 , 1 term=5, 8 terms=6 and 10 terms=7 --> 18th term is 6.

Re: Yesterday each of the 35 members of a certain task force [#permalink]
21 Sep 2013, 14:49

A little unorthodox approach, but so far it has worked for these types of problems. I set up the number of people that worked that many hours in a number line:

9 - 4 - 1 - 2 - 1 - 8 - 10

As Bunuel said we have 35 terms so the middle, 18th term, will be the median.

I then start crossing off from either end until I find the "1" remaining:

9 4 1 2 1 8 10 0 4 1 2 1 8 1 0 3 1 2 1 8 0 0 0 1 2 1 5 0 0 0 0 2 1 4 0 0 0 0 0 1 2 0 0 0 0 0 0 1 0 - Therefore it's the sixth term, in this case "6 hours"....hope it makes sense, just a minor shortcut over writing out all 35 terms.

gmatclubot

Re: Yesterday each of the 35 members of a certain task force
[#permalink]
21 Sep 2013, 14:49

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