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You have 4 jars of pills. Each pill is a certain weight,

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You have 4 jars of pills. Each pill is a certain weight, [#permalink] New post 10 Sep 2008, 20:30
You have 4 jars of pills. Each pill is a certain weight, except for contaminated pills contained in one jar, where each pill is weight + 1. How could you tell which jar had the contaminated pills in just one measurement?
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Re: Fun Math [#permalink] New post 10 Sep 2008, 21:10
GMAT TIGER wrote:
You have 4 jars of pills. Each pill is a certain weight, except for contaminated pills contained in one jar, where each pill is weight + 1. How could you tell which jar had the contaminated pills in just one measurement?


each pill weight =w
contaminated pill weight=w+1


Take different no of pills from 4 jackets.

For e.g
from Jar1 1 pill
from Jar 2 2 pills
from Jar 3 3 pills
from Jar 4 4

weight total pills = w+2w+3w+4w + x (x-- contaminated pills extra weight)
= 10w+x

once you measured the weight.. find x

if x=1 -- first jar
if x=2 second jar
if x=3 third jar.
if x=4 4th jar.

Where did you find this question..

very interesting..

It took 7 minutes to answer this question.
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Re: Fun Math [#permalink] New post 10 Sep 2008, 21:23
x2suresh wrote:
GMAT TIGER wrote:
You have 4 jars of pills. Each pill is a certain weight, except for contaminated pills contained in one jar, where each pill is weight + 1. How could you tell which jar had the contaminated pills in just one measurement?


each pill weight =w
contaminated pill weight=w+1


Take different no of pills from 4 jackets.

For e.g
from Jar1 1 pill
from Jar 2 2 pills
from Jar 3 3 pills
from Jar 4 4

weight total pills = w+2w+3w+4w + x (x-- contaminated pills extra weight)
= 10w+x

once you measured the weight.. find x

if x=1 -- first jar
if x=2 second jar
if x=3 third jar.
if x=4 4th jar.

Where did you find this question..

very interesting..

It took 7 minutes to answer this question.


you can find anywhere else. just google:

try this: Suppose you had 8 billiard balls, and one of them was slightly heavier, but the only way to tell was by putting it on a scale against another. What's the fewest number of times you'd have to use the scale to find the heavier ball?
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Gmat: everything-you-need-to-prepare-for-the-gmat-revised-77983.html


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Re: Fun Math [#permalink] New post 10 Sep 2008, 22:07
[quote="GMAT TIGER
try this: Suppose you had 8 billiard balls, and one of them was slightly heavier, but the only way to tell was by putting it on a scale against another. What's the fewest number of times you'd have to use the scale to find the heavier ball?[/quote]


Will it be 3?

step 1: 4 balls on each side of the scale. Get the heavier side balls.
step 2: 2 balls on each side of the scale from the lot of balls of heavier side in step 1. Get the heavier side balls.
step 3: 1 ball on each side of the scale. Get the heavier ball.
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Re: Fun Math [#permalink] New post 11 Sep 2008, 04:06
scthakur wrote:
[quote="GMAT TIGER
try this: Suppose you had 8 billiard balls, and one of them was slightly heavier, but the only way to tell was by putting it on a scale against another. What's the fewest number of times you'd have to use the scale to find the heavier ball?



Will it be 3?

step 1: 4 balls on each side of the scale. Get the heavier side balls.
step 2: 2 balls on each side of the scale from the lot of balls of heavier side in step 1. Get the heavier side balls.
step 3: 1 ball on each side of the scale. Get the heavier ball.[/quote]

agreed.


These questions... sound similar to sankunthala devi puzzles..
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Re: Fun Math   [#permalink] 11 Sep 2008, 04:06
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You have 4 jars of pills. Each pill is a certain weight,

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