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# Your input is greatly appreciated! Thanks. OA: D

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Your input is greatly appreciated! Thanks. OA: D [#permalink]  07 Feb 2007, 21:43
Your input is greatly appreciated! Thanks.

OA: D
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Re: Gmatprep - area [#permalink]  07 Feb 2007, 21:53
joyce wrote:
Your input is greatly appreciated! Thanks.

OA: D

Here you need to remember the property of equilateral triangle. For equilateral triangle the height will bisect the base hence it will divide the base in to 2 equal parts and in this case it will be t/2 and t/2

Now we can find the height by pythagoras theorem:

t^2 = (t/2)^2 + h^2
t^2 = t^2/4 + h^2
h^2 = t^2 - t^2/4
h^2 = 3t^2/4
h = sq. rt(3) * t/2

Hence area of the triangle = 1/2 * t * t/2 * sq. rt(3)
= sq. rt(3) * t^2/4

Now area of square = s^2
s^2 = sq. rt(3) * t^2/4

s/t = 3^1/4 / 2

t/s = 2 / 3^1/4
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Re: Gmatprep - area   [#permalink] 07 Feb 2007, 21:53
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