Bunuel received 2 Kudos for post Re: x= sqrt(8xy-16y^2), in terms of y , x = ?.

GiverPostDate
MittyRe: x= sqrt(8xy-16y^2), in terms of y , x = ?04-Nov-2016
pritish2301Re: x= sqrt(8xy-16y^2), in terms of y , x = ?17-Oct-2012

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