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Bunuel received 2 Kudos for post Re: p^a*q^b*r^c*s^d=x, where x is a perfect square. If p, q, r.

GiverPostDate
chayandRe: p^a*q^b*r^c*s^d=x, where x is a perfect square. If p, q, r06-Aug-2023
M3tm4nRe: p^a*q^b*r^c*s^d=x, where x is a perfect square. If p, q, r14-Feb-2012

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