| Giver | Post | Date |
| Markella24 | Re: If x>=0 and x=root(8xy - 16y^2) then, in terms of y, x= | 14-Feb-2022 |
| ShaikhMoice | Re: If x>=0 and x=root(8xy - 16y^2) then, in terms of y, x= | 27-May-2021 |
| TESCHNL | Re: If x>=0 and x=root(8xy - 16y^2) then, in terms of y, x= | 07-Apr-2018 |
| Mitty | Re: If x>=0 and x=root(8xy - 16y^2) then, in terms of y, x= | 04-Nov-2016 |
| pritish2301 | Re: If x>=0 and x=root(8xy - 16y^2) then, in terms of y, x= | 17-Oct-2012 |