| Giver | Post | Date |
| leamari02 | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 03-Dec-2023 |
| Francis21 | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 28-Nov-2023 |
| Aniket03 | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 13-Nov-2023 |
| dalt555 | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 18-Sep-2023 |
| hdixit | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 08-Sep-2023 |
| sonalirai97 | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 16-Aug-2023 |
| sandarbhbhardwaj | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 11-Aug-2023 |
| Its_me_aka_ak | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 09-Aug-2023 |
| suranamohit2694 | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 09-Aug-2023 |
| ishika.8 | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 21-Jun-2023 |
| SS.56 | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 30-May-2023 |
| kar12tikey | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 14-Aug-2022 |
| AmanRathod | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 05-Aug-2022 |
| Madiha0108 | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 03-Aug-2022 |
| SanjuktaMukherjee | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 27-Jul-2022 |
| Vashisthas | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 25-Jul-2022 |
| EshaL | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 24-Jul-2022 |
| sg41093 | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 23-Jul-2022 |
| JAIDEEP27 | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 23-Jul-2022 |
| anoushkaa23 | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 22-Jul-2022 |
| LuisBendel | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 07-Apr-2022 |
| prashantjanghel | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 01-Apr-2022 |
| sachidanandhari | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 02-Feb-2022 |
| Poojasheoran173 | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 19-Jan-2022 |
| architasanare | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 17-Jan-2022 |
| vinitsharmaa1205 | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 14-Jan-2022 |
| ktttttt | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 12-Jan-2022 |
| JhalakJain20 | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 11-Jan-2022 |
| khumoyuns | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 20-Aug-2021 |
| AS06222326 | Given: 4^(2t+1) - 4^(t+2) = 128, find t | 01-Jul-2021 |