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2
The answer is “A”
First Integer – x
Second Integer – x+2
Third Integer – x+4
S1 x+y is even=x+x+2=2x+2=2(x+1)=True
S2(x+z)/y=(x+x+4)/(x+2)=(2x+4)/(x+2)=2(x+2)/(x+2)=2=Integer=True
S3xz=x(x+4)=x^2+4x=Odd+Even=Odd=False
Ans 😀