If a point is arbitrarily selected inside a circle of radius , what is the probability that the distance from this point to the center of the circle will be greater than ?

A.

B.

C.

D.

E.

Question Discussion & Explanation

**Correct Answer** - B - (click and drag your mouse to see the answer)

**Verbal**

His campaign for sanitary conditions in operating rooms finally successful, Sir Joseph Lister lent his name to the company that developed Listerine, the first antibacterial liquid.

(A) His campaign for sanitary conditions in operating rooms finally successful

(B) Since his campaign for sanitary conditions in operating rooms had been eventually successful

(C) Because of the eventual success of his campaigning for sanitary conditions in operating rooms

(D) His campaign for sanitary conditions in operating rooms being eventually successful

(E) Campaigning, eventually successfully, for conditions to be sanitary in operating rooms

**Correct Answer** - A - (click and drag your mouse to see the answer)

**Like these questions?** Get the GMAT Club question collection: online at GMAT Club OR on your Kindle OR on your iPhone/iPad

*Jennifer Land shares the Kaplan Method for effective answer prediction.*

One of the things I love about being a Kaplan GMAT teacher is that my students learn a method for answering every question they will face on Test Day. Having a consistent approach makes answering a high-difficulty GMAT question as simple as answering its lower-difficulty cousin. Each step is the same, the steps are performed in the same order, and with practice the Kaplan Methods become my students’ methods.

Learning to use the Kaplan Methods, like learning to use any tools, requires practice. For example, the **Kaplan Method for Critical Reasoning** is a logical series of steps aimed at saving time through prediction:

- Identify the question type.
- Untangle the stimulus.
- Predict the answer.
- Evaluate the choices.

Although the steps are logical, their order may seem a bit counterintuitive. Before discussing the Kaplan Method for Critical Reasoning, most of my students would perform only three of these steps, and they would follow this order: Step 2 (read it), Step 1 (ID the question), then Step 4 (read the choices).

The first thing you see on a Critical Reasoning question **isn’t the question**; it’s the stimulus. So **reading the question first** is easy to forget! To apply the prediction method to its greatest advantage, you have to practice **looking at the question before you untangle the stimulus**. Without knowing what you are looking for (by identifying the question type), you may need to reread the stimulus, which will waste precious Test Day time.

Steps 2 and 4, deciphering the stimulus and reading the answer choices, are logical and don’t require much discussion in my classroom. However, I find that Step 3 bears frequent repeating. I usually write it in all caps: PREDICT THE ANSWER. It flows from the previous steps; once you’ve read the question, you know, for example, whether you need to identify an assumption or weaken the argument. Then, once you take apart the stimulus, you know what that assumption or weakener should be. Voila! All that remains is finding the match.

Prediction takes just a few seconds of critical thinking. Novice GMAT-takers will read the stimulus and then the question, then assess each answer choice; by applying the Kaplan Method and predicting what you are looking for before you read the answer choices, you will** save time and increase your accuracy**. And that will certainly go a long way toward helping you land your best score.

*Want to practice your Critical Reasoning answer prediction? Take our **free GMAT pop quiz** to check your Test Day readiness.*

The post Land Your Score: Critical Reasoning Answer Prediction appeared first on Business School Insider.

]]>If a price was increased by % and then decreased by %, is the new price higher than the original?

(1)

(2)

Question Discussion & Explanation

**Correct Answer** - E - (click and drag your mouse to see the answer)

**Verbal**

First published in 1946, and comparing the ways the world appears both in Homer’s Odyssey and in the Bible, Mimesis, a philosophical treatise written by Auerbach, laid the foundation for a unified theory of western literature beginning from the very early times to his days.

(A) and comparing the ways the world appears both in Homer’s Odyssey and in the Bible, Mimesis, a philosophical treatise written by Auerbach, laid the foundation for a unified theory of western literature beginning from the very early times to his days

(B and laying the foundation for a unified theory of western literature beginning from the very early times to his days, Mimesis, a philosophical treatise written by Auerbach compared the ways the world appears both in Homer’s Odyssey and in the Bible

(C) Mimesis, a philosophical treatise written by Auerbach, compares the ways the world appears both in Homer’s Odyssey and in the Bible, and lays the foundation for a unified theory of western literature beginning from the very early times to his days

(D) and comparing the ways the world appears both in Homer’s Odyssey and in the Bible, Mimesis, a philosophical treatise written by Auerbach, lays the foundation for a unified theory of western literature beginning from the very early times to his days

(E) and comparing Homer’s Odyssey with the Bible and the ways the world appears in both , Mimesis, a philosophical treatise written by Auerbach laid the foundation for a unified theory of western literature beginning from the very early times to his days

**Correct Answer** - A - (click and drag your mouse to see the answer)

**Like these questions?** Get the GMAT Club question collection: online at GMAT Club OR on your Kindle OR on your iPhone/iPad

]]>

1) Let abcd be a general four-digit number and all the digits are non-zero. How many four-digits numbers abcd exist such that the four digits are all distinct and such that a + b + c = d?

(A) 6

(B) 7

(C) 24

(D) 36

(E) 42

2) Let abcd be a general four-digit number. How many odd four-digits numbers abcd exist such that the four digits are all distinct, no digit is zero, and the product of a and b is the two digit number cd?

(A) 4

(B) 6

(C) 12

(D) 24

(E) 36

3) There are 500 cars on a sales lot, all of which have either two doors or four doors. There are 165 two-door cars on the lot. There are 120 four-door cars that have a back-up camera. Eighteen percent of all the cars with back-up cameras have standard transmission. If 40% of all the cars with both back-up cameras and standard transmission are two-door cars, how many four-door cars have both back-up cameras and standard transmission?

(A) 18

(B) 27

(C) 36

(D) 45

(E) 54

4) At Mnemosyne Middle School, there are 700 students: all the students are boys or girls in the 4^{th} or 5^{th} grade. There are 320 students in the 4^{th} grade, and there are 210 girls in the 5^{th} grade. Fifty percent of the 5^{th} graders and 40% of the 4^{th} graders take Mandarin Chinese. Ninety 5^{th} grade boys do not take Mandarin Chinese. The number of 4^{th} grade girls taking Mandarin Chinese is less than half of the number of 5^{th} grade girls taking Mandarin Chinese. Which of the following could be the number of 5^{th} grade boys in Mandarin Chinese?

(A) 10

(B) 40

(C) 70

(D) 100

(E) 130

5) A hundred identical cubic boxes are currently arranged in four cubes: a single cubic box, a 2 x 2 x 2 cube, a 3 x 3 x 3 cube, and a 4 x 4 x 4 cube. These four are not touching each other. All outward faces are painted and all inward faces are not painted. These four cubes are going to be dismantled and reassembled as a flat 10 x 10 square. The top and all the edges of this 10 x 10 square must be painted, but there is no requirement for paint on the bottom. How many individual faces will have to be painted to accommodate the requirements of this new design?

(A) 0

(B) 5

(C) 9

(D) 16

(E) 27

6) Twelve points are spaced evenly around a circle, lettered from A to L. Let N be the total number of isosceles triangles, including equilateral triangles, that can be constructed from three of these points. A different orientation of the same lengths counts as a different triangle, because a different combination of points form the vertices. What is the value of N?

(A) 48

(B) 52

(C) 60

(D) 72

(E) 120

7) Theresa is a basketball player practicing her free throws. On her first free throw, she has a 60% chance of making the basket. If she has just made a basket on her previous throw, she has a 80% of making the next basket. If she has just failed to make a basket on her previous throw, she has a 40% of making the next basket. What is the probability that, in five throws, she will make at least four baskets?

8) Suppose a “Secret Pair” number is a four-digit number in which two adjacent digits are equal and the other two digits are not equal to either one of that pair or each other. For example, 2209 and 1600 are “Secret Pair” numbers, but 1333 or 2552 are not. How many “Secret Pair” numbers are there?

(A) 720

(B) 1440

(C) 1800

(D) 1948

(E) 2160

9) In the coordinate plane, a circle with its center on the negative x-axis has a radius of 12 units, and passes through (0, 6) and (0, – 6). What is the area of the part of this circle in the first quadrant?

10) In the coordinate plane, line L passes above the points (50, 70) and (100, 89) but below the point (80, 84). Which of the following could be the slope of line L?

(A) 0

(B) 1/2

(C) 1/4

(D) 2/5

(E) 6/7

11) At the beginning of the year, an item had a price of A. At the end of January, the price was increased by 60%. At the end of February, the new price was decreased by 60%. At the end of March, the new price was increased by 60%. At the end of April, the new price was decreased by 60%. On May 1^{st}, the final price was approximately what percent of A?

(A) 41%

(B) 64%

(C) 100%

(D) 136%

(E) 159%

12) Suppose that, at current exchange rates, $1 (US) is equivalent to Q euros, and 1 euro is equivalent to 7Q Chinese Yuan. Suppose that K kilograms of Chinese steel, worth F Chinese Yuan per kilogram, sold to a German company that paid in euros, can be fashioned into N metal frames for chairs. These then are sold to an American company, where plastic seats & backs will be affixed to these frames. If the German company made a total net profit of P euros on this entire transaction, how much did the US company pay in dollars for each frame?

13) At the Zamenhof Language School, at least 70% of the students take English each year, at least 40% take German each year, and between 30% and 60% take Italian each year. Every student must take at least one of these three languages, and no student is allowed to take more than two languages in the same year. What is the possible percentage range for students taking both English and German in the same year?

(A) 0% to 70%

(B) 0% to 100%

(C) 10% to 70%

(D) 10% to 100%

(E) 40% to 70%

14) On any given day, the probability that Bob will have breakfast is more than 0.6. The probability that Bob will have breakfast **and** will have a sandwich for lunch is less than 0.5. The probability that Bob will have breakfast **or** will have a sandwich for lunch equals 0.7. Let P = the probability that, on any given day, Bob will have a sandwich for lunch. If all the statements are true, what possible range can be established for P?

(A) 0 < P < 0.6

(B) 0 ≤ P < 0.6

(C) 0 ≤ P ≤ 0.6

(D) 0 < P < 0.7

(E) 0 ≤ P < 0.7

(A) – 64

(B) – 7

(C) 38

(D) 88

(E) 128

Explanations for this problem are at the end of this article.

Here are twenty-eight other articles on this blog with free GMAT Quant practice questions. Some have easy questions, some have medium, and few have quite challenging questions.

1) GMAT Geometry: Is It a Square?

2) GMAT Shortcut: Adding to the Numerator and Denominator

3) GMAT Quant: Difficult Units Digits Questions

4) GMAT Quant: Coordinate Geometry Practice Questions

5) GMAT Data Sufficiency Practice Questions on Probability

6) GMAT Quant: Practice Problems with Percents

7) GMAT Quant: Arithmetic with Inequalities

8) Difficult GMAT Counting Problems

9) Difficult Numerical Reasoning Questions

10) Challenging Coordinate Geometry Practice Questions

11) GMAT Geometry Practice Problems

12) GMAT Practice Questions with Fractions and Decimals

13) Practice Problems on Powers and Roots

14) GMAT Practice Word Problems

15) GMAT Practice Problems: Sets

16) GMAT Practice Problems: Sequences

17) GMAT Practice Problems on Motion

18) Challenging GMAT Problems with Exponents and Roots

19) GMAT Practice Problems on Coordinate Geometry

20) GMAT Practice Problems: Similar Geometry Figures

20) GMAT Practice Problems: Variables in the Answer Choices

21) Counting Practice Problems for the GMAT

22) GMAT Math: Weighted Averages

23) GMAT Data Sufficiency: More Practice Questions

24) Intro to GMAT Word Problems, Part I

25) GMAT Data Sufficiency Geometry Practice Questions

26) GMAT Data Sufficiency Logic: Tautological Questions

27) GMAT Quant: Rates and Ratios

28) Absolute Value Inequalities

These are hard problems. When you read the solutions, don’t merely read them passively. Study the strategies used, and do what you can to retain them. Learn from your mistakes!

1) We need sets of three distinct integers {a, b, c} that have a sum of one-digit number d. There are seven possibilities:

- a) {1, 2, 3}, sum = 6
- b) {1, 2, 4}, sum = 7
- c) {1, 2, 5}, sum = 8
- d) {1, 3, 4}, sum = 8
- e) {1, 2, 6}, sum = 9
- f) {1, 3, 5}, sum = 9
- g) {2, 3, 4}, sum = 9

For each set, the sum-digit has to be in the one’s place, but the other three digits can be permutated in 3! = 6 ways in the other three digits. Thus, for each item on that list, there are six different possible four-digit numbers. The total number of possible four-digit numbers would be 7*6 = 42. Answer =** (E)**

2) The fact that abcd is odd means that cd must be an odd number and that a & b both must be odd. That limits the choices significantly. We know that neither a nor b can equal 1, because any single digit number times 1 is another single digit number, and we need a two-digit product—there are no zeros in abcd. We also know that neither a nor b can equal 5, because any odd multiple of 5 ends in 5, and we would have a repeated digit: the requirement is that all four digits be distinct.

Therefore, for possible values for a & b, we are limited to three odd digits {3, 7, 9}. We can take three different pairs, and in each pair, we can swap the order of a & b. Possibilities:

- use {3, 7}, product = 21, abcd could be 3721 or 7321
- use {3, 9}, product = 27, abcd could be 3927 or 9327
- use {7, 9}, product = 63, abcd could be 7963 or 9763

Those six are the only possibilities for abcd.

Answer = **(B)**

3) Total number of cars = 500

2D cars total = 165, so

4D cars total = 335

120 4D cars have BUC

“*Eighteen percent of all the cars with back-up cameras have standard transmission*.”

18% = 18/100 = 9/50

This means that the number of cars with BUC must be a multiple of 50.

How many 2D cars can we add to 120 4D cars to get a multiple of 50? We could add 30, or 80, or 130, but after that, we would run out of 2D cars. These leaves three possibilities for the total number with BUC:

If a total of 150 have BUC, then 18% or 27 of them also have ST.

If a total of 200 have BUC, then 18% or 36 of them also have ST.

If a total of 250 have BUC, then 18% or 45 of them also have ST.

Then we are told: “*40% of all the cars with both back-up cameras and standard transmission are two-door car*.”

40% = 40/100 = 2/5

This means that number of cars with both back-up cameras and standard transmission must be divisible by 5. Of the three possibilities we have, only the third words.

Total cars with BUC cams = 250 (120 with 4D and 130 with 2D)

18% or 45 of these also have ST.

40% of that is 18, the number of 2D cars with both BUC and ST.

Thus, the number of 4D cars with both BUC and ST would be

45 – 18 = 27

Answer = **(B)**

4) 700 student total

4G = total number of fourth graders

5G = total number of fifth graders

We are told 4G = 320, so 5G = 700 – 320 = 380

5GM, 5GF = fifth grade boys and girls, respectively

We are told 5GF = 210, so 5GM = 380 – 210 = 170

4GC, 5GC = total number of 4^{th} or 5^{th} graders, respectively taking Chinese

We are told

5GC = 0.5(5G) = 0.5(380) = 190

4GC = 0.4(4G) = 0.4(320) = 128

4GFM, 4GMC, 5GFC, 5GMC = 4^{th}/5^{th} grade boys & girls taking Chinese

We are told that, of the 170 fifth grade boys, 90 do not take Chinese, so 170 = 90 = 80 do. Thus 5GMC = 80.

5GMC + 5GFC = 5GC

80 + 5GFC = 190

5GFC = 110

We are told:

4GFM < (0.5)(5GFC)

4GFM < (0.5)(100)

4GFM < 55

Thus, 4GFM could be as low as zero or as high as 54.

4GMC = 4GC – 4GFM

If 4GFM = 0, then 4GMC = 128 – 0 = 128

If 4GFM = 54, then 4GMC = 128 – 54 = 74

Thus, fourth grade boys taking Mandarin Chinese could take on any value N, such that 74 ≤ N ≤ 128. Of the answer choices listed, the only one that works is 100.

Answer = **(D)**

5) The single cube has paint on all six sides. Each of the eight boxes in the 2 x 2 x 2 cube has paint on three sides (8 corner pieces). In the 3 x 3 x 3 cube, there are 8 corner pieces, 12 edge pieces (paint on two sides), 6 face pieces (paint on one side), and one interior piece (no paint). In the 4 x 4 x 4 cube, there are 8 corner pieces, 24 edge pieces, 24 face pieces, and 8 interior pieces. This chart summarizes what we have:

For the 10 x 10 flat square, we will need 4 corner pieces that have paint on three sides, 32 edge pieces that have paint on two sides (top & side), and 64 middle pieces that have paint on one side (the top).

We could use either the single total box or any of the 24 corner boxes for the four corners of the square. That leaves 21 of these, and 35 edge boxes, more than enough to cover the 32 edges of the square. The remaining ones, as well as all 30 face boxes, can be turned paint-side-up to fill in the center. The only boxes that will need to be painted, one side each, are the 9 interior boxes. Thus, we have 9 sides to paint.

Answer = **(C)**

6) Here’s a diagram.

First, let’s count the equilateral triangles. They are {AEI, BFJ, CGK, DHL}. There are only four of them.

Now, consider all possible isosceles triangles, excluding equilateral triangles, with point A as the vertex. We could have BAL, CAK, DAJ, and FAH. All four of those have a line of symmetry that is vertical (through A and G). Thus, we could make those same four triangles with any other point as the vertex, and we would never repeat the same triangle in the same orientation. That’s 4*12 = 48 of these triangles, plus the 4 equilaterals, is 52 total triangles.

Answer = **(B)**

7) There are five basic scenarios for this:

__Case I__: (make)(make)(make)(make)(any)

If she makes the first four, then it doesn’t matter if she makes or misses the fifth!

__Case II__: (miss)(make)(make)(make)(make)

__Case III__: (make)(miss)(make)(make)(make)

__Case IV__: (make)(make)(miss)(make)(make)

__Case V__: (make)(make)(make)(miss)(make)

Put in the probabilities:

__Case I__: (0.6)(0.8)(0.8)(0.8)

__Case II__: (0.4)(0.4)(0.8)(0.8)(0.8)

__Case III__: (0.6)(0.2)(0.4)(0.8)(0.8)

__Case IV__: (0.6)(0.8)(0.2)(0.4)(0.8)

__Case V__: (0.6)(0.8)(0.8)(0.2)(0.4)

Since all the answers are fractions, change all of those to fractions. Multiply the first by (5/5) so it has the same denominator as the other products.

__Case I__: (3/5)(4/5)(4/5)(4/5)(5/5) = 960/5^5

__Case II__: (2/5)(2/5)(4/5)(4/5)(4/5) = 256/5^5

__Case III__: (3/5)(1/5)(2/5)(4/5)(4/5) = 96/5^5

__Case IV__: (3/5)(4/5)(1/5)(2/5)(4/5) = 96/5^5

__Case V__: (3/5)(4/5)(4/5)(1/5)(2/5) = 96/5^5

Add the numerators. Since 96 = 100 – 4, 3*96 = 3(100 – 4) = 300 – 12 = 288.

288 + 256 + 960 = 1504

P = 1504/5^5

Answer = **(E)**

8) There are three cases: AABC, ABBC, and ABCC.

In case I, AABC, there are nine choices for A (because A can’t be zero), then 9 for B, then 8 for C. 9*9*8 = 81*8 = 648.

In case II, ABBC, there are 9 choices for A, 9 for B, and 8 for C. Again, 648.

In case III, ABCC, there are 9 choices for A, 9 for B, and 8 for C. Again, 648.

48*3 = (50 – 2)*3 = 150 – 6 = 144

3*648 = 3(600 + 48) = 1800 + 144 = 1948

Answer = **(D)**

9)

We know that the distance from A (0,6) to B (0, – 6) is 12, so triangle ABO is equilateral. This means that angle AOB is 60°. The entire circle has an area of

A 60° angle is 1/6 of the circle, so the area of sector AOB (the “slice of pizza” shape) is

The area of an equilateral triangle with side s is

Equilateral triangle AOB has s = 12, so the area is

If we subtract the equilateral triangle from the sector, we get everything to the right of the x-axis.

Again, that’s everything to the right of the x-axis, the parts of the circle that lie in Quadrants I & IV. We just want the part in Quadrant I, which would be exactly half of this.

Answer = **(C)**

10) One point is (50, 70) and one is (100, 89): the line has to pass above both of those. Well, round the second up to (100, 90)—if the line goes above (100, 90), then it definitely goes about (100, 89)!

What is the slope from (50, 70) to (100, 90)? Well, the rise is 90 – 70 = 20, and the run is 100 – 50 = 50, so the slope is rise/run = 20/50 = 2/5. A line with a slope of 2/5 could pass just above these points.

Now, what about the third point? For the sake of argument, let’s say that the line has a slope of 2/5 and goes through the point (50, 71), so it will pass above both of the first two points. Now, move over 5, up 2: it would go through (55, 73), then (60, 75), then (65, 77), then (70, 79), then (75, 81), then (80, 83). This means it would pass under the third point, (80, 84). A slope of 2/5 works for all three points.

We don’t have to do all the calculations, but none of the other slope values works.

Answer = **(D)**

11) The trap answer is 100%: a percent increase and percent decrease by the same percent do not cancel out.

Let’s say that the A = $100 at the beginning of the year.

End of January, 60% increase. New price = $160

End of February, 60% decrease: that’s a decrease of 60% of $160, so that only 40% of $160 is left.

10% of $160 = $16

40% of $160 = 4(16) = $64

That’s the price at the end of February.

End of March, a 60% increase: that’s a increase of 60% of $64.

10% of $64 = $6.40

60% of $64 = 6(6 + .40) = 36 + 2.4 = $38.40

Add that to the starting amount, $64:

New price = $64 + $38.40 = $102.40

End of April, 60% decrease: that’s a decrease of 60% of $102.40, so that only 40% of $102.40 is left.

At this point, we are going to approximate a bit. Approximate $102.40 as $100, so 40% of that would be $40. The final price will be slightly more than $40.

Well, what is slightly more than $40, as a percent of the beginning of the year price of $100? That would be slightly more than 40%.

Answer = **(A)**

12) The K kilograms, worth F Chinese Yuan per kilogram, are worth a total of KF Chinese Yuan. The German company must pay this amount.

Since 1 euro = (7Q) Chinese Yuan, then (1/(7Q)) euro = 1 Chinese Yuan, and (KF/7Q) euros = KF Chinese Yuan. That’s the amount that the Germans pay to the Chinese.

That is the German company’s outlay, in euros. Now, they make N metal chairs, and sell them, making a gross profit of P euros.

That must be the total revenue of the German company, in euros. This comes from the sale to the American company. Since $1 = Q euros, $(1/Q) = 1 euro, so we change that entire revenue expression to euros to dollars, we divide all terms by Q.

That must be the total dollar amount that leaves the American company and goes to the German company. This comes from the sale of N metal frames for chairs, so each one must have been 1/N of that amount.

Answer = **(A)**

13) First, we will focus on the least, the lowest value. Suppose the minimum of 70% take English, and the minimum of 40% take German. Even if all 30% of the people not taking English take German, that still leaves another 10% of people taking German who also have to be taking English. Thus, 10% is the minimum of this region.

Now, the maximum. Both the German and English percents are “at least” percents, so either could be cranked up to 100%. The trouble is, though, that both can’t be 100%, because some folks have to take Italian, and nobody can take three languages at once. The minimum taking Italian is 30%. Let’s assume all 100% take German, and that everyone not taking Italian is taking English: that’s 70% taking English, all of whom also would be taking German. Thus, 70% is the maximum of this region.

Answer = **(C)**

14) Let A = Bob eats breakfast, and B = Bob has a sandwich for lunch. The problem tells us that:

P(A) > 0.6

P(A and B) < 0.5

P(A or B) = 0.7

First, let’s establish the minimum value. If Bob never has a sandwich for lunch, P(B) = 0, then it could be that P(A and B) = 0, which is less than 0.5, and it could be that P(A) = 0.7, which is more than 0.6, so that P(A or B) = 0.7. All the requirements can be satisfied if P(B) = 0, so it’s possible to equal that minimum value.

Now, the maximum value. Since P(A or B) = 0.7, both P(A) and P(B) must be contained in this region. See the conceptual diagram.

The top line, 1, is the entire probability space. The second line, P(A or B) = 0.7, fixes the boundaries for A and B. P(A) is the purple arrow, extending from the right. P(B) is the green arrow extending from the left. The bottom line, P(A and B) < 0.5, is the constraint on their possible overlap.

Let’s say that P(A) is just slightly more than 0.6. That means the region outside of P(A), but inside of P(A or B) is slightly less than 1. That’s the part of P(B) that doesn’t overlap with P(A). Then, the overlap has to be less than 0.5. If we add something less than 1 to something less than 5, we get something less than 6. P(B) can’t equal 0.6, but it can any value arbitrarily close to 0.6.

Thus, 0 ≤ P(B) < 0.6.

Answer = **(B)**

15)

Answer = **(E)**

The post Challenging GMAT Math Practice Questions appeared first on Magoosh GMAT Blog.

]]>If you have a strong business school application, you likely won’t need a near-perfect GMAT score for admission into a top MBA program. But how do you know if your GMAT score is up to par with your dream school’s GMAT requirements? Have no fear; we’ve collected GMAT score data from the admissions offices of all the top business schools to bring you the most recent data in average GMAT scores by school.

** Special update:** We’ve collected the very most recent information for average GMAT scores by school for the top 10 business schools in the United States. See the section immediately below.

**Note:** This is the most up-to-date information on average GMAT scores by school, GMAT requirements by schools, and other important statistics. All data for Harvard GMAT scores, Stanford GMAT scores, and the rest (including school ranking), comes from U.S. News and Word Report.

Name of MBA Program/Business School | Average GMAT Score | Rank | Enrollment, 2016-2017 |
---|---|---|---|

Harvard Business School |
725 | 1 | 1,872 |

Stanford Graduate School of Business |
733 | 2 (tie) | 824 |

University of Chicago(Booth) |
726 | 2 (tie) | 1,180 |

University of Pennsylvania(Wharton) |
732 | 4 | 1,715 |

Northwestern University(Kellogg) |
724 | 5 (tie) | 1,272 |

Massachusetts Institute of Technology(Sloan) |
716 | 5 (tie) | 806 |

University of California-Berkeley(Haas) |
715 | 7 | 502 |

Yale School of Management |
761 | 8 (tie) | 668 |

Dartmouth(Tuck) |
717 | 8 (tie) | 563 |

Columbia Business School |
715 | 10 | 1,287 |

Of course, there’s a lot more out there than just the top 10. When it comes to finding your fit and researching MBA programs, the ranking numbers don’t tell the whole story.

Scroll down to see average GMAT scores for a wide range of reputable b-schools in the USA.

**Note:**** **This information is recent, but is not quite as up-to-date as the date in the table above. Still, these stats should give you a pretty good idea of these schools’ GMAT requirements and expectations. More updates will be coming soon. In the meantime, use this table to get a general idea of where you stand with each school.

(Click the image to open the infographic in a new page and zoom in/out!)

*Important to note: officially, the GMAT scale for verbal and quantitative goes up to 60, but in practice, the scale tops out at 51. Nowadays, a verbal subscore of 46 would get you in the 99th GMAT score percentile, while a 51 quant subscore would be in the 97th.*

To accurately assess your GMAT score, you must understand the big picture of GMAT admissions, and remember that your GMAT score is just one part of your application.

First, familiarize yourself with GMAT scoring. Then, compare your score to the average GMAT scores by school of admitted students at your target programs. Keep in mind that an average score for a top business school is not the bare minimum you need to get in–approximately half of applicants get into that school with less than that average score. (In other words, not all Wharton students attained a 732 score even though that’s the average Wharton GMAT score). That means you can think about it as just that–an average score.

If your GMAT is good enough for the programs you like (say, for example, you want to go to University of Chicago and your score is a 726, just as Booth’s GMAT score is a 726), then focus your energy on strengthening other aspects of your application. And if your score doesn’t quite make the cut, then consider retaking the GMAT only so you can distinguish yourself from other applicants with a similar application profile to yours.

Ultimately, you have to decide what is a good GMAT score for you. GMAT scores may be paramount to the application process, but even a 720 combined score won’t get you into the best business schools without a strong application to back it up. Your entire profile must honestly and effectively represent your successes, abilities, and potential.

Still … a 720 can’t hurt.

If you’ve checked out an average GMAT score by school and think you need help getting there, then reach out about our Magoosh GMAT Prep! And while you’re at it, leave us a comment below with your thoughts about this infographic.

The post GMAT Scores for Top MBA Programs appeared first on Magoosh GMAT Blog.

]]>How many positive three-digit integers are not divisible by 3 ?

A. 599

B. 600

C. 601

D. 602

E. 603

Question Discussion & Explanation

**Correct Answer** - B - (click and drag your mouse to see the answer)

**Verbal**

At the annual stockholders meeting, investors heard a presentation on the numerous challenges facing the company, including among them the threat from a rival’s multibillion-dollar patent-infringement suit and the declining sales for the company’s powerful microprocessor chip.

A. including among them the threat from a rival’s multibillion-dollar patentinfringement suit and the declining sales for

B. which includes the threat of a rival’s multibillion-dollar patent-infringement suit and declining sales of

C. included among these the threat from a rival’s multibillion-dollar patentinfringement suit as well as a decline in sales for

D. among them the threat of a rival’s multibillion-dollar patent-infringement suit and the decline in sales of

E. among these the threat from a rival’s multibillion-dollar patent-infringement suit as well as the decline in sales for

Question Discussion & Explanation

**Correct Answer** - D - (click and drag your mouse to see the answer)

**Like these questions?** Get the GMAT Club question collection: online at GMAT Club OR on your Kindle OR on your iPhone/iPad

*This article is brought to you by Uloop and Kaplan. Search Uloop for student housing, college roommates, sublets, part-time jobs, internships, tutors, and campus news.*

Everyone knows that students are busy. Juggling school, work, and a social life is difficult — it’s something we can all agree on.

Most of us make New Year’s resolutions, and oftentimes, those resolutions include getting in shape. In fact, the number one resolution (by a high margin) for 2017 was to lose weight and eat healthier, while life- and self-improvements was number two, and work out more often was number seven.

This is especially true for students trying to shave or stave off the freshman fifteen! But now that those New Year’s resolutions are behind us, students might need some more motivation to do so. There are plenty of options to help you get into gear and keep working out.

Read on to learn how to stay fit without the gym with some quick and easy home and dorm workouts!

Most people have a smartphone or similar device, whether it is an Android or an Apple product. So why not bring the gym to you and work out where you and your smartphone happen to be? There are plenty of apps that can help you be your best self and get into shape.

You can choose based on your interests — do you want to lose weight? Do you want to beef up? Do you just want to be active and healthy? Do not make yourself miserable doing a workout you do not enjoy when there are so many options and kinds of workouts available to you, and with these apps, available to you in the comfort of your own room or home.

No time to stop at the gym? Only have time to work out when the gym is closed? These apps can help you out because you can do the workout whenever and wherever! Whether you like yoga, running, or strength training, find the workout that makes you fulfilled.

Marie Claire suggests the following apps as especially great for working out at home:

•Sworkit

•Keelo

•Charity Miles

•Daily Ab Workout

•Daily Butt Workout

•Daily Yoga

•Nike+Training Club

•The Johnson & Johnson 7 Minute Work Out

•Fitstar Personal Trainer

•Relax Melodies

Another really simple step to take to give you a little workout is to travel the extra distance by taking more steps. This can manifest in many different ways, like taking the stairs, walking instead of driving, and parking far away from your intended destination.

There are stairs all around us, maybe at your apartment complex, at your residence hall, at your work, at school. Do your best to always take the stairs when it is an option. It might seem like a little thing but it will add up, staircase after staircase, and day after day. If climbing stairs seems daunting, work your way towards full stair climbing. You can start by only climbing downstairs, or by only taking the stairs if you are going up two levels or less. You do not want to start too strong and injure yourself by pushing yourself too far right away.

Maybe you live close enough to campus that you could walk if you had to but you often do not feel like it, whether that be because of weather or time constraints. Maybe you could walk to your grocery store instead of drive, even if you have to carry your groceries. Maybe you could even walk to your mailbox rather than stopping at it as you drive by. Baby steps.

If something is in walking distance, try walking to it. It can help you to get exercise as well as de-stress, unwind, and clear your head. Give yourself a few minutes each day to unplug and just enjoy your surroundings. Walking where you can is a good start.

Another little tactic to try to help you get more steps in is to park far away from your intended destination. Maybe you have to pick something up from the grocery store. Rather than parking in the closest spot you can find, park all the way at the back of the lot so you have further to go. Maybe you need to drive to campus (you get out of class really late at night or you have to go to work after class). Instead of parking in the nearest parking garage, park in one that is a little bit further away and enjoy the trek across campus.

How often do you get to just walk and enjoy the sights your campus has to offer? From puppies catching balls to students LARPing to others just laying out in the sun, let yourself be amused by the smallest details of life while getting a good little workout into your day.

*For more college news, and to search for off-campus housing, tutors near campus, and jobs for college students, go to Uloop.com. *

The post Staying Fit Without the Gym: Quick and Easy Home/Dorm Workouts appeared first on Business School Insider.

]]>Project A requires $2000 of investment and promises a return of % per year. Project B requires $3000 of investment and promises a return of % per year. If the yearly return from project B is 50% greater than that from project A, what is ?

A. 0

B. 1

C. 5

D. 10

E. 15

Question Discussion & Explanation

**Correct Answer** - A - (click and drag your mouse to see the answer)

**Verbal**

Originally delivered as the first William James Lecture at Harvard, in 1932, John Dewey in his major writing on aesthetics, Art as Experience, declares that through an expressive art, the artists and the audience commune together, an encounter that reminds man and mankind of their responsibilities towards each other

(A) Originally delivered as the first William James Lecture at Harvard, in 1932, John Dewey in his major writing on aesthetics, Art as Experience, declares that through an expressive art, the artists and the audience commune together, an encounter that reminds

(B) Originally delivered as the first William James Lecture at Harvard in 1932, Art as Experience, John Dewey’s major writing on aesthetics declares that through an expressive art, the artists and the audience commune together, an encounter that reminds

(C) Originally delivering Art as Experience as the first William James Lecture at Harvard in 1932, John Dewey in his major writing on aesthetics declares that through an expressive art, the artists and the audience commune together, an encounter that reminds

(D) Originally delivered as the first William James Lecture at Harvard in 1932, Art as Experience, John Dewey’s major writing on aesthetics declared that through such an expressive art, the artists and the audience communed together, an encounter that reminded

(E) When it was originally delivered as the first William James Lecture at Harvard in 1932, Art as Experience, John Dewey’s major writing on aesthetics declared that through an expressive art, the artists and the audience communed together, an encounter that reminds

Question Discussion & Explanation

**Correct Answer** - C - (click and drag your mouse to see the answer)

**Like these questions?** Get the GMAT Club question collection: online at GMAT Club OR on your Kindle OR on your iPhone/iPad

A rectangular floor measures 2 by 3 meters. There are 5 white, 5 black, and 5 red parquet blocks available. If each block measures 1 by 1 meter, in how many different color patterns can the floor be parqueted?

A. 104

B. 213

C. 577

D. 705

E. 726

Question Discussion & Explanation

**Correct Answer** - E - (click and drag your mouse to see the answer)

**Verbal**

Bioconservatives, a group who believe that technological innovation threatens the existing social order, predict the opposite as techno-progressives, who believe that, when properly regulated, technology can empower and emancipate.

(A) a group who believe that technological innovation threatens the existing social order, predict the opposite as techno-progressives, who believe that, when properly regulated, technology can empower and emancipate

(B) a group who believes that technological innovation threatens the existing social order, predict the opposite of what techno-progressives, who believe that, when properly regulated, technology can empower and emancipate, forecast

(C) a group that believes that technological innovation threatens the existing social order, predicts the opposite of techno-progressives, who believe that, when properly regulated, technology can empower and emancipate

(D) a group who believe that technological innovation threatens the existing social order, predict the opposite of believing that, when properly regulated, technology can empower and emancipate

(E) believing that technological innovation threatens the existing social order, predict the opposite of techno-progressives, who believe that, when properly regulated, technology can empower and emancipate

Question Discussion & Explanation

**Correct Answer** - B - (click and drag your mouse to see the answer)

**Like these questions?** Get the GMAT Club question collection: online at GMAT Club OR on your Kindle OR on your iPhone/iPad