{"id":4986,"date":"2010-11-15T09:00:55","date_gmt":"2010-11-15T17:00:55","guid":{"rendered":"https:\/\/gmatclub.com\/blog\/?p=4986"},"modified":"2010-11-09T02:57:20","modified_gmt":"2010-11-09T10:57:20","slug":"data-sufficiency-before-you-pick-c","status":"publish","type":"post","link":"https:\/\/gmatclub.com\/blog\/data-sufficiency-before-you-pick-c\/","title":{"rendered":"Data Sufficiency: Before you pick C&#8230;"},"content":{"rendered":"<p>To succeed on the GMAT, there is a general rule of Algebra that you should know: to solve for all variables in a system of equations, you need as many distinct linear equations as variables.  So if you get 2 variables, you need two equations; three variables, three equations, and so on.  With that in mind, think about this Data Sufficiency question:<\/p>\n<p>What is the value of <img src='https:\/\/s0.wp.com\/latex.php?latex=x&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x' title='x' class='latex' \/>?<br \/>\n(1)\t<img src='https:\/\/s0.wp.com\/latex.php?latex=2x+%2B+3y+%3D+8&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='2x + 3y = 8' title='2x + 3y = 8' class='latex' \/><br \/>\n(2)\t<img src='https:\/\/s0.wp.com\/latex.php?latex=3x-5y+%3D+-7&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='3x-5y = -7' title='3x-5y = -7' class='latex' \/><\/p>\n<p>We have two variables, and once we get both statements, we\u2019ll have two equations, so we\u2019ll be able to solve for <img src='https:\/\/s0.wp.com\/latex.php?latex=x&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x' title='x' class='latex' \/>.  The answer is (C), or the third Data Sufficiency answer choice\u2014together the statements are sufficient.  If you\u2019ve figured this out, that\u2019s awesome.  You\u2019ve discovered how to save a lot of time on Test Day.   <\/p>\n<p>But I always tell students not to get trigger-happy.  Before you pick (C), keep in mind that the GMAT often gives you situations in which we can get sufficiency with just one equation, or when two won\u2019t be enough.   Here are three of those situations:<\/p>\n<p><strong>The Vanishing Variable<\/strong><\/p>\n<p>What is the value of <img src='https:\/\/s0.wp.com\/latex.php?latex=x&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x' title='x' class='latex' \/>?<br \/>\n(1)\t<img src='https:\/\/s0.wp.com\/latex.php?latex=3x%2B4y+%3D+2%28x+%2B2y%29%2B3&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='3x+4y = 2(x +2y)+3' title='3x+4y = 2(x +2y)+3' class='latex' \/><br \/>\n(2)\t<img src='https:\/\/s0.wp.com\/latex.php?latex=4x+%3D+y-2&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='4x = y-2' title='4x = y-2' class='latex' \/><\/p>\n<p>Both equations have two variables, so how could one possibly be sufficient to solve for <img src='https:\/\/s0.wp.com\/latex.php?latex=x&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x' title='x' class='latex' \/>?  Let\u2019s play with Statement (1) a bit so we can isolate <img src='https:\/\/s0.wp.com\/latex.php?latex=x&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x' title='x' class='latex' \/>.  Distribute the right side of the equation to get <img src='https:\/\/s0.wp.com\/latex.php?latex=3x%2B4y+%3D+2x+%2B4y%2B3&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='3x+4y = 2x +4y+3' title='3x+4y = 2x +4y+3' class='latex' \/>.  Then we can subtract <img src='https:\/\/s0.wp.com\/latex.php?latex=4y&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='4y' title='4y' class='latex' \/> from both sides, and poof!  We have a single variable equation.  We certain can solve for <img src='https:\/\/s0.wp.com\/latex.php?latex=x&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x' title='x' class='latex' \/>.  The answer is (A), statement 1 alone is sufficient to answer the question.  So before you settle for (C), ask yourself if you can eliminate a variable from one equation.<\/p>\n<p><strong>Solving for a Relationship<\/strong><\/p>\n<p>What is the value of <img src='https:\/\/s0.wp.com\/latex.php?latex=2x+-+y&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='2x - y' title='2x - y' class='latex' \/>?<br \/>\n(1)\t<img src='https:\/\/s0.wp.com\/latex.php?latex=6x+%2B+3y%3D+15&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='6x + 3y= 15' title='6x + 3y= 15' class='latex' \/><br \/>\n(2)\t<img src='https:\/\/s0.wp.com\/latex.php?latex=6x+-+3y+%3D+-3&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='6x - 3y = -3' title='6x - 3y = -3' class='latex' \/><\/p>\n<p>When the GMAT asks you to solve for a relationship between variables (a sum, difference, product, or quotient), ask yourself, Can I manipulate one of the statements to solve for that relationship?  If you can do this, you\u2019ll only need one equation for sufficiency.  In this case, no amount of manipulating of Statement 1 can do the trick, but let\u2019s play with Statement 2.   Divide both sides by 3, and you get <img src='https:\/\/s0.wp.com\/latex.php?latex=2x+-+y+%3D+-1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='2x - y = -1' title='2x - y = -1' class='latex' \/>.  We still don\u2019t know what <img src='https:\/\/s0.wp.com\/latex.php?latex=x&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x' title='x' class='latex' \/> or <img src='https:\/\/s0.wp.com\/latex.php?latex=y&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='y' title='y' class='latex' \/> is, but we <em>do<\/em> know what <img src='https:\/\/s0.wp.com\/latex.php?latex=2x+-+y&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='2x - y' title='2x - y' class='latex' \/> is.  The answer is (B), statement 2 alone is sufficient. <\/p>\n<p><strong>The Disguised Twin<\/strong><\/p>\n<p>What is the value of <img src='https:\/\/s0.wp.com\/latex.php?latex=x&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x' title='x' class='latex' \/>?<br \/>\n(1)\t<img src='https:\/\/s0.wp.com\/latex.php?latex=2x%2B5y+%3D+12&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='2x+5y = 12' title='2x+5y = 12' class='latex' \/><br \/>\n(2)\t<img src='https:\/\/s0.wp.com\/latex.php?latex=4x+%3D+24+-+10y&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='4x = 24 - 10y' title='4x = 24 - 10y' class='latex' \/><\/p>\n<p>It seems like we have everything we need to pick (C) here.  Two equations, two variables, we\u2019re golden.  Except dig a little deeper; Statement (2) should cause D\u00e9j\u00e0 vu.  Add 10y to both sides of the second equation <img src='https:\/\/s0.wp.com\/latex.php?latex=4x+%2B10y+%3D+24&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='4x +10y = 24' title='4x +10y = 24' class='latex' \/> and divide everything by 2, and you\u2019ll discover that the two equations are identical\u2014just dressed up a little differently.  Since we really have just one equation with two variables, we have a recipe for insufficiency.  The answer is (E), there is not enough information within these statements to answer the question, no matter how you use them or combine them.<\/p>\n<p><strong>Going forward<\/strong><\/p>\n<p>So you don\u2019t necessarily have to solve these systems of equations when you see them in a DS question, but you will have to do some detective work before you pick (C).  As we advise students in our newly revised GMAT courses, ask yourself the following questions when assessing this type of problem:  Can you make a variable vanish?  Can you solve for the desired relationship by manipulating an equation?   Are these equations really different?  When you know the anatomy of the test, you score higher.<\/p>\n<p>Ben Leff<br \/>\n<a href=\"https:\/\/bit.ly\/KaptestGMAT\">Kaplan GMAT<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>To succeed on the GMAT, there is a general rule of Algebra that you should know: to solve for all variables in a system of equations, you need as many&#8230;<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[9,558],"tags":[384,1894,583,678,593,381,511,574,220,645,361],"class_list":["post-4986","post","type-post","status-publish","format-standard","hentry","category-gmat","category-kaplan-blog","tag-data-sufficiency","tag-gmat","tag-gmat-advice","tag-gmat-data-sufficiency","tag-gmat-ds","tag-gmat-math","tag-gmat-quant","tag-gmat-strategy","tag-gmat-test","tag-gmat-tip","tag-gmat-tips","entry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/gmatclub.com\/blog\/wp-json\/wp\/v2\/posts\/4986","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gmatclub.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gmatclub.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gmatclub.com\/blog\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/gmatclub.com\/blog\/wp-json\/wp\/v2\/comments?post=4986"}],"version-history":[{"count":2,"href":"https:\/\/gmatclub.com\/blog\/wp-json\/wp\/v2\/posts\/4986\/revisions"}],"predecessor-version":[{"id":4988,"href":"https:\/\/gmatclub.com\/blog\/wp-json\/wp\/v2\/posts\/4986\/revisions\/4988"}],"wp:attachment":[{"href":"https:\/\/gmatclub.com\/blog\/wp-json\/wp\/v2\/media?parent=4986"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gmatclub.com\/blog\/wp-json\/wp\/v2\/categories?post=4986"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gmatclub.com\/blog\/wp-json\/wp\/v2\/tags?post=4986"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}