{"id":7712,"date":"2011-06-28T03:45:49","date_gmt":"2011-06-28T11:45:49","guid":{"rendered":"https:\/\/gmatclub.com\/blog\/?p=7712"},"modified":"2011-06-28T03:45:49","modified_gmt":"2011-06-28T11:45:49","slug":"gmat-question-of-the-day-jun-28-mixture-problem-and-critical-reasoning","status":"publish","type":"post","link":"https:\/\/gmatclub.com\/blog\/gmat-question-of-the-day-jun-28-mixture-problem-and-critical-reasoning\/","title":{"rendered":"GMAT Question of the Day (Jun 28): Mixture Problem and Critical Reasoning"},"content":{"rendered":"<p><strong>Math (DS)<\/strong><\/p>\n<p><img src='https:\/\/s0.wp.com\/latex.php?latex=X&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='X' title='X' class='latex' \/> grams of water were added to the 80 grams of a strong solution of acid. As a result, the concentration of acid in the solution became <img src='https:\/\/s0.wp.com\/latex.php?latex=%5Cfrac%7B1%7D%7BY%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\\frac{1}{Y}' title='\\frac{1}{Y}' class='latex' \/> times of the initial concentration. What was the concentration of acid in the original solution?<\/p>\n<p>   1. <img src='https:\/\/s0.wp.com\/latex.php?latex=X+%3D+80&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='X = 80' title='X = 80' class='latex' \/><br \/>\n   2. <img src='https:\/\/s0.wp.com\/latex.php?latex=Y+%3D+2&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='Y = 2' title='Y = 2' class='latex' \/> <\/p>\n<div style=\"background-color: rgb(141, 179, 226); border-top: 4px solid rgb(0, 0, 0); border-bottom: 4px solid rgb(0, 0, 0); padding: 5px; margin-left: 20px; font-size: 15px; font-family: Gergia,serif; font-weight: bold\">\n<div style=\"font-size: 19px; color: rgb(255, 255, 255); margin-bottom: 10px; padding-left: 10px\">GMAT Daily Deals<\/div>\n<ul>\n<li style=\"padding: 0pt 0pt 10px 20px; color: rgb(255, 255, 255); list-style-type: disc\">Join Kaplan in their Road to Business School. Seminars, meet and greets, and admission advice. <a href=\"https:\/\/click.linksynergy.com\/fs-bin\/click?id=PJTlq5NYqfE&offerid=216481.10000973&subid=blog&type=4\" style=\"color: rgb(0, 0, 255);\"><u>Register now!<\/u><\/a><\/li>\n<li style=\"padding: 0pt 0pt 0px 20px; color: rgb(255, 255, 255); list-style-type: disc\">Get a free profile evaluation by Amerasia Prep and save 15% on services when you mention GMAT Club. <a href=\"https:\/\/gmatclub.com\/static\/forward.php?r=https:\/\/gmatclub.com\/forum\/ask-paul-lanzillotti-153\/\" style=\"color: rgb(0, 0, 255);\"><u>Learn more!<\/u><\/a><\/li>\n<\/ul>\n<\/div>\n<p><\/p>\n<p><strong>Verbal (CR)<\/strong><\/p>\n<p>Paper&Print is a chain of British stores selling magazines, books, and stationery products. In Britain, magazines' retail prices are set by publishers, and the retailer's share of a magazine's retail price is 25 percent. Since Paper&Print's margin on books and stationery products is much higher, the chain's management plans to devote more of its stores' shelf space to books and stationery products and reduce the number of magazine titles that its stores carry.<\/p>\n<p>Which of the following, if true, most strongly argues that the plan, if put into effect, will not increase Paper&Print's profits?<\/p>\n<p>(A) Recently magazine publishers, seeking to increase share in competitive sectors of the market, have been competitively cutting the retail prices of some of the largest circulation magazines.<br \/>\n(B) In market research surveys, few consumers identify Paper&Print as a book or stationery store but many recognize and value the broad range of magazines it carries.<br \/>\n(C) The publisher's share of a magazine's retail price is 50 percent, and the publisher also retains all of the magazine's advertising revenue.<br \/>\n(D) Consumers who subscribe to a magazine generally pay less per issue than they would if they bought the magazine through a retail outlet such as Paper&Print.<br \/>\n(E) Some of Paper& Print's locations are in small towns and represent the only retail outlet for books within the community.<\/p>\n<div style=\"color:#cecece\">\nAnswers to the questions: <strong>E<\/strong>, <strong>B<\/strong><br \/>\nFor explanations please see these threads: <a href=\"https:\/\/gmatclub.com\/forum\/m24-71126.html\">math<\/a> and <a href=\"https:\/\/gmatclub.com\/forum\/cr-paperprint-65446.html\">verbal<\/a>\n<\/div>\n<p><\/p>\n<p><strong>Like these questions?<\/strong> Get the GMAT Club question collection: <a href=\"https:\/\/gmatclub.com\/tests\/\">online at GMAT Club<\/a> OR <a href=\"https:\/\/www.amazon.com\/gp\/redirect.html?ie=UTF8&location=http%3A%2F%2Fwww.amazon.com%2Fgp%2Fentity%2FGMAT-Club%2FB0048PPF3U%3Fie%3DUTF8%26ref_%3Dntt_athr_dp_pel_1&tag=gmatclub-20&linkCode=ur2&camp=1789&creative=390957\">on your Kindle<\/a> OR <a href=\"https:\/\/click.linksynergy.com\/fs-bin\/stat?id=PJTlq5NYqfE&offerid=146261&type=3&subid=blog&tmpid=1826&RD_PARM1=http%253A%252F%252Fitunes.apple.com%252Fus%252Fapp%252Fgmat-toolkit%252Fid328345537%253Fmt%253D8%2526uo%253D6%2526partnerId%253D30\">on your iPhone\/iPad<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Math (DS) grams of water were added to the 80 grams of a strong solution of acid. As a result, the concentration of acid in the solution became times of&#8230;<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[152,9,721,718],"tags":[],"class_list":["post-7712","post","type-post","status-publish","format-standard","hentry","category-gmat-tests","category-gmat","category-critical-reasoning-gmat","category-data-sufficiency-gmat","entry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/gmatclub.com\/blog\/wp-json\/wp\/v2\/posts\/7712","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gmatclub.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gmatclub.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gmatclub.com\/blog\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/gmatclub.com\/blog\/wp-json\/wp\/v2\/comments?post=7712"}],"version-history":[{"count":1,"href":"https:\/\/gmatclub.com\/blog\/wp-json\/wp\/v2\/posts\/7712\/revisions"}],"predecessor-version":[{"id":7713,"href":"https:\/\/gmatclub.com\/blog\/wp-json\/wp\/v2\/posts\/7712\/revisions\/7713"}],"wp:attachment":[{"href":"https:\/\/gmatclub.com\/blog\/wp-json\/wp\/v2\/media?parent=7712"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gmatclub.com\/blog\/wp-json\/wp\/v2\/categories?post=7712"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gmatclub.com\/blog\/wp-json\/wp\/v2\/tags?post=7712"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}