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# 1/(1+1/3)-1/(1+1/2)

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Math Expert
Joined: 02 Sep 2009
Posts: 41886

Kudos [?]: 128688 [1], given: 12182

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26 Aug 2012, 02:59
1
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Expert's post
1
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Difficulty:

5% (low)

Question Stats:

90% (00:31) correct 10% (00:39) wrong based on 1535 sessions

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$$\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}$$

(A) -1/3
(B) -1/6
(C) -1/12
(D) 1/12
(E) 1/3

Practice Questions
Question: 27
Page: 155
Difficulty: 550
[Reveal] Spoiler: OA

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Kudos [?]: 128688 [1], given: 12182

Math Expert
Joined: 02 Sep 2009
Posts: 41886

Kudos [?]: 128688 [0], given: 12182

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26 Aug 2012, 02:59
SOLUTION:

$$\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}$$

(A) -1/3
(B) -1/6
(C) -1/12
(D) 1/12
(E) 1/3

$$\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}=\frac{1}{(\frac{4}{3})}-\frac{1}{(\frac{3}{2})}=\frac{3}{4}-\frac{2}{3}=\frac{1}{12}$$.

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Kudos [?]: 128688 [0], given: 12182

Senior Manager
Status: Prevent and prepare. Not repent and repair!!
Joined: 13 Feb 2010
Posts: 253

Kudos [?]: 124 [0], given: 282

Location: India
Concentration: Technology, General Management
GPA: 3.75
WE: Sales (Telecommunications)

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26 Aug 2012, 08:22
By taking the LCM and taking the reciprocals-

3/4-2/3=1/12
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I've failed over and over and over again in my life and that is why I succeed--Michael Jordan
Kudos drives a person to better himself every single time. So Pls give it generously
Wont give up till i hit a 700+

Kudos [?]: 124 [0], given: 282

Intern
Joined: 21 Apr 2010
Posts: 11

Kudos [?]: 4 [0], given: 2

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27 Aug 2012, 11:07
Ans = (3/4) - (2/3) = 1/12

Kudos [?]: 4 [0], given: 2

Intern
Joined: 28 Aug 2012
Posts: 4

Kudos [?]: 5 [0], given: 2

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28 Aug 2012, 04:10

3/4 - 2/3 = 1/12

Kudos [?]: 5 [0], given: 2

Senior Manager
Joined: 06 Aug 2011
Posts: 390

Kudos [?]: 233 [0], given: 82

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28 Aug 2012, 08:28
bunuel.. i think difficulty level shud be 500 or below 500..

its 1/12.. person shud knw the 1+1/3 = 4/3.. by not taking LCM because that will waste ur time..
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Bole So Nehal.. Sat Siri Akal.. Waheguru ji help me to get 700+ score !

Kudos [?]: 233 [0], given: 82

Math Expert
Joined: 02 Sep 2009
Posts: 41886

Kudos [?]: 128688 [0], given: 12182

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31 Aug 2012, 01:53
SOLUTION:

$$\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}$$

(A) -1/3
(B) -1/6
(C) -1/12
(D) 1/12
(E) 1/3

$$\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}=\frac{1}{(\frac{4}{3})}-\frac{1}{(\frac{3}{2})}=\frac{3}{4}-\frac{2}{3}=\frac{1}{12}$$.

_________________

Kudos [?]: 128688 [0], given: 12182

GMAT Club Legend
Joined: 09 Sep 2013
Posts: 16712

Kudos [?]: 273 [0], given: 0

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22 Apr 2014, 03:27
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Kudos [?]: 273 [0], given: 0

Senior Manager
Status: Professional GMAT Tutor
Affiliations: AB, cum laude, Harvard University (Class of '02)
Joined: 10 Jul 2015
Posts: 404

Kudos [?]: 477 [1], given: 53

Location: United States (CA)
Age: 37
GMAT 1: 770 Q47 V48
GMAT 2: 730 Q44 V47
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GRE 1: 337 Q168 V169
WE: Education (Education)

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10 May 2016, 18:18
1
KUDOS
Attached is a visual that should help.
Attachments

Screen Shot 2016-05-10 at 5.50.27 PM.png [ 75.73 KiB | Viewed 7333 times ]

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Harvard grad and 770 GMAT scorer, offering high-quality private GMAT tutoring, both in-person and via Skype, since 2002.

McElroy Tutoring

Kudos [?]: 477 [1], given: 53

Intern
Joined: 10 May 2016
Posts: 10

Kudos [?]: [0], given: 15

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11 May 2016, 02:59
1/(4/3)-1/(3/2)= 3/4- 2/3= 9-8/12=1/12

Kudos [?]: [0], given: 15

GMAT Club Legend
Joined: 09 Sep 2013
Posts: 16712

Kudos [?]: 273 [0], given: 0

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14 Jul 2017, 23:32
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
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Kudos [?]: 273 [0], given: 0

Re: 1/(1+1/3)-1/(1+1/2)   [#permalink] 14 Jul 2017, 23:32
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