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1/(1+1/3)-1/(1+1/2)

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New post 26 Aug 2012, 02:59
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Difficulty:

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\(\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}\)

(A) -1/3
(B) -1/6
(C) -1/12
(D) 1/12
(E) 1/3

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Difficulty: 550
[Reveal] Spoiler: OA

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New post 26 Aug 2012, 02:59
SOLUTION:

\(\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}\)

(A) -1/3
(B) -1/6
(C) -1/12
(D) 1/12
(E) 1/3

\(\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}=\frac{1}{(\frac{4}{3})}-\frac{1}{(\frac{3}{2})}=\frac{3}{4}-\frac{2}{3}=\frac{1}{12}\).

Answer: D.
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Re: 1/(1+1/3)-1/(1+1/2) [#permalink]

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New post 26 Aug 2012, 08:22
By taking the LCM and taking the reciprocals-

3/4-2/3=1/12
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New post 27 Aug 2012, 11:07
Ans = (3/4) - (2/3) = 1/12

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New post 28 Aug 2012, 04:10
Answer is 1/12

3/4 - 2/3 = 1/12

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New post 28 Aug 2012, 08:28
bunuel.. i think difficulty level shud be 500 or below 500..

its 1/12.. person shud knw the 1+1/3 = 4/3.. by not taking LCM because that will waste ur time..
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New post 31 Aug 2012, 01:53
SOLUTION:

\(\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}\)

(A) -1/3
(B) -1/6
(C) -1/12
(D) 1/12
(E) 1/3

\(\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}=\frac{1}{(\frac{4}{3})}-\frac{1}{(\frac{3}{2})}=\frac{3}{4}-\frac{2}{3}=\frac{1}{12}\).

Answer: D.
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Collection of Questions:
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Re: 1/(1+1/3)-1/(1+1/2) [#permalink]

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New post 10 May 2016, 18:18
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Attached is a visual that should help.
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Screen Shot 2016-05-10 at 5.50.27 PM.png [ 75.73 KiB | Viewed 7333 times ]


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New post 11 May 2016, 02:59
1/(4/3)-1/(3/2)= 3/4- 2/3= 9-8/12=1/12

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Re: 1/(1+1/3)-1/(1+1/2)   [#permalink] 14 Jul 2017, 23:32
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